A new sneaker claims that it can make male athletes jump higher. A sample of 47 male athletes were asked to jump once with their own sneakers on and once wearing the new sneakers. The average jump increased by 2.15 inches with the new sneakers with a standard deviation of 1.38 inches. What is the standard error of the 95% confidence interval for the average jump increase?
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- researchers are concerned about the impact of students working while they are enrolled in classes, and they would like to know if students work too muc and therefore are spending less time on their classes than they should be. first the researchers need to find out, on average , how many hours a week students are working. A survey of 50 students provides a sample mean of 7.1 hours work with the standard deviation of 5 hours. what is a 95% confidence interval based on this sample? The 95 % confidence interval for the number of hours worked from _________hours to _________hours.Please help!Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two populations, individuals who drink alcohol and individuals who do not drink alcohol. The mean ALT levels for the individuals who do not drink alcohol is 32 with a standard deviation of 14, and 37 individuals were in the sample. The mean ALT levels for individuals who drink alcohol is 69 with a standard deviation of 19, and 38 individuals were in the sample. Construct and interpret a 95% confidence interval demonstrating the difference in means for those individuals who drink alcohol when compared to those who do not drink alcohol.
- In a survey, 29 people were asked how much they spent on their child's birthday gift. The results were roughly bell-shaped with a mean of $46.8 and standard deviation of $5.8. Estimate how much a typical parent would spend on their child's birthday gift using a 98% confidence interval. Express the answer in the format of x +- E.A random sample of 10 children found that their average growth for the first year was 9.8 inches, with a standard deviation of 0.96 inches. Find the 85% confidence interval of the mean growth of all American children in the first year of life.What is the name of the confidence interval?The mean length of 25 newly hatched iguanas is 7.47 inches with a standard deviation of 0.77 inches. Assume that the lengths of all newly hatched iguanas are normally distributed. Step 1 of 2 : Calculate the margin of error for a 98% confidence interval. Round your answer to two decimal places.
- Helga is researching the IQ of a particular monkey species. She measured the IQ in 15 monkeys with a special monkey IQ test and it turned out to be 120 points on average. The standard deviation was 12 points. It can be assumed that the IQ follows a normal distribution. What is the upper limit of the 95% confidence interval for the average monkey species index?Suppose we have only ten scores representing the ages (in years) of randomly selected U.S. commercial aircraft. The average age of the ten aircraft is 14.25 years and the sample standard deviation is 9.349 years. Construct a 95% confidence interval for the mean age of all U.S. commercial aircraft. I would appreciate to see what formulas you use and the work through because I messed up.A random sample of 64 shoppers showed that they spend an average of $27.31 per visit at the Sunday Mornings Bookstore. The standard deviation of the population is $2.14. Find the 90% confidence interval of the true mean. Please include all work showing how you found your answer.
- A researcher is interested in finding a 98% confidence interval for the mean number of times per day that college students text. The study included 110 students who averaged 33.1 texts per day. The standard deviation was 16.8 texts. Round answers to 3 decimal places where possibleChristina wants to know the true average number of pages in a typical textbook. She randomly selects 196 books, and they have an average of 161 pages. Calculate a 90.3% confidence interval if you are given that the standard deviation for a single book is 75 pages.Albert, a student of statistics, considered a random sample of the duration of 100 phone calls. He constructed the confidence interval with 95% confidence. Veronica selected her own random sample of 100 phone calls and constructed a confidence interval with 95% confidence. Is it possible that the confidence interval she obtained is different from the one Albert obtained? Explain why or why not. Suppose that they do not have information about the standard deviation of the population