A new pump is required for the water supply system of a high-rise office building. The system requires 0.06 m³/s of water pumped to a reservoir at the top of the tower 340 m above the street. City water pressure at the street-level pump inlet is 400 kPa gage. The piping is to be commercial steel, the overall length is 20 percent greater than the tower height, and there are fittings every 10 m with loss coefficients of 0.2. Determine the minimum diameter required to keep the average water velocity below 3.5 m/s in the pipe. Calculate the pressure rise required across the pump and estimate the minimum power needed to drive the pump.

A liquid (SG = 0.8 and μ = 5 CP = 0.00336 lbm/ft s) from a solvent recovery plant is being pumped from a vessel into a reactor. The flow rate to the rector is 100 GPM (0.2228 ft³/s,) and the line, schedule 40-carbon steel (a = 0.0018 in). The pressure in the vessel is 15 psig and the reactor is pressurized to 65 psig. The flow into the reactor is 25 ft below the level in the vessel as shown in the drawing. The centrifugal pump is located 5 ft below the level in the vessel. The piping consists of the following: Suction line 10 ft of 2.5" Pipe Gate valves 90 degree elbows Check valves 2" sch 40 pipe 2.5" Sch 40 pipe Gate valve Check Valve 90° elbows 2 2 1 ID = 2.067" ID=2.47" K = 8 ft K= 100 fr K = 30 ff Discharge line 325 ft of 2" 2 5 none Acs=0.0233 ft² Acs = 0.0332 ft² a. Determine the velocity in the 2.5" and 2" lines (ft /s). b. Determine the losses due to friction in both the suction and discharge lines (ft lbi/lbm). c. Estimate the amount of total dynamic head required of the pump…

The system consists of: 1. Stainless steel pipes with a diameter of 5 cm and a total length of 200 meters. 2. Four control valves distributed throughout the system. 3. Two centrifugal pumps in series, each with an efficiency of 80%. Over the past few weeks, a pressure of 20 bar has been recorded at the inlet of the first pump, but only 15 bar at the outlet of the second pump. Furthermore, the flow rate has decreased from 10 m³/h to 7 m³/h. It has been noted that one of the control valves is showing signs of wear and may not be functioning properly. Calculates the pressure loss in the system, taking into account the length of the pipes, the material, the valves and the pumps.

What is the pressure drop in the turbine? Answer: 1176.91 kPa (replace “turbine pressure drop” for “pump pressure increase”)

I need help on this question: According to the question: a) If the pipe connected to the pump inlet has a diameter of 24 mm with length (LCP) of 5 m and Darcy friction factor of 0.03, what would be the actual head rise across the pump for a case where the pump outlet pressure is 200 kPa? The difference in height between pump inlet and outlet is 0.25 m, the tank exit is sharp-edged, and the water level in the tank to the tank exit pipe (HWL) is 2 m. Also, consider that the flow velocity inside the tank is negligible. The value of the actual head rise across the pump is = ? b) What would be the pump motor power if the efficiency is 60%? The value of the pump motor power is = ?

A hydroelectric station operates under a mean head of 30 m. The reservoir employed has a catchment area of 4× 10 m². The rainfall in this area is 125 cm per annum. Determine the capacity of the station for which it should be designed. Assume that 30% of the rainfall is lost due to evaporation etc, 5 per cent of the head is lost in penstock , turbine efficiencies as 85% ,alternator efficiency as 90% and load factor as 50% .

Parvinbhai

Part A: Water at 20 °C (p = 998.3 and v= kg 1 x 10-6 m²/s) flows through a galvanised iron pipe (k = 0.15 mm) with a diameter of 20 mm, entering the room at point A and discharging at point C from the fully opened gate valve B at a volumetric flow rate of 0.003 m³/s. Determine the required pressure at A, considering all the losses that occur in the system described in Figure Q1. Loss coefficients for pipe fittings have been provided in Table 1. L₂=L3 at L₁ = L₁ = 3 =L4= A L₂ La L5 L3 B Figure Q1. Pipe system 3 =26=1 L5=0-5 20 mm

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