A new insecticide is advertised to kill more than 95% roaches upon contact. In a laboratory test, the insecticide was applied to 400 roaches and 384 died immediately after contact. Is this sufficient evidence to support the advertised claim? Use α=0.05. (a) Alternative hypothesis for the problem above is
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A new insecticide is advertised to kill more than 95% roaches upon contact. In a laboratory test, the insecticide was applied to 400 roaches and 384 died immediately after contact.
Is this sufficient evidence to support the advertised claim? Use α=0.05.
(a) Alternative hypothesis for the problem above is
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- A survey of 90 recently delivered women on the rolls of a county welfare department revealed that 27 had a history of intrapartum or postpartum infection. Can we conclude that the population proportion with a history of intrapartum or postpartum infection is significantly less than or equal to 0.25? Let alpha = 0.05.A new insecticide is advertised to kill more than 95% roaches upon contact. In a laboratory test, the insecticide was applied to 400 roaches and 384 died immediately after contact. Is this sufficient evidence to support the advertised claim? Use α=0.05. (c) p-value for the problem above iA tax accountant would like to test the claim that the proportion of individuals who owe when filing their taxes is greater than 0.20. If the z− test statistic was calculated as z=1.94, does the tax accountant have enough evidence to reject the null hypothesis? Assume α=0.05.
- In a random survey of 500 doctors that practice specialized medicine, 125 felt that the government should control health care. In a random sample of 800 doctors that were general practitioners, 240 felt that the government should control health care. Test the claim that there is a difference in the proportions. Use α = 0.10.A question of medical interest is whether jogging leads to a reduction in systolic blood pressure. To learn about this question, eight non-jogging volunteers have agreed to begin a 1-month jogging program. At the end of the month, their blood pressures were determined and compared with earlier values. The data are presented in the Table 1. a. The appropriate hypotheses are: H0 :μ1−μ2 =0 versus Ha :μ1−μ2 /= (does not equal) 0 H0 :μ1−μ2 =0 versus Ha :μ1−μ2 <0 H0 :μ1−μ2 =0 versus Ha :μ1−μ2 >0 b. The value of test statistic is 1. 0.577 2. −0.577 3. 0.237 4. -0.237 c. The p−value of test is 1. 0.816 2. 0.408 3. 0.582 4. 0.291 d. At the significance level calculated in part (c), we conclude that jogging i. Leads to reduction in systolic blood pressureii. Does not lead to reduction in systolic blood pressureState the null and alternative hypotheses. We want to test if the most popular brand of soda contains 355ml. We want to test if the average recovery time for knee surgery patients is 8.2 weeks when exposed to a thorough exercise program.
- 8% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 367 people from the inner city surveyed, 37 of them suffered from sleep apnea. What can be concluded at the level of significance of α = 0.05? Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger than 8% at α = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 8%. The data suggest the population proportion is not significantly larger than 8% at α = 0.05, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 8%. The data suggest the populaton proportion is significantly larger than 8% at α = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have…A poll of 700 frequent and occasional fliers found that 450 respondents favored a ban on cellphones in flight, even if technology permits it. At α = .05, can we conclude that morethan half the sampled population supports a ban?. It is known 35% of women with long hair have split ends. A hair stylist believes this proportion is smaller for her clients using her salon. A sample of 178 women with long hair using her salon, showed 33.96% have split ends. Is there enough evidence to support her claim at α = .03 (by hand)
- A medical researcher wishes to try three different techniques to lower cholesterol levels of patients with high cholesterol levels. The subjects are randomly selected and assigned to one of three groups. Group 1 is given medication, Group 2 is given an exercise program, and Group 3 is assigned a diet program. At the end of six weeks, each subject's cholesterol level is recorded. Test the hypothesis that there is no difference among the means. Use α = 0.05. Apply p-value approach. Round p-value to nearest thousandth. Show step1-step3. Group1 Group2 Group3 11 8 8 12 3 12 13 10 4 15 6 6 9 0 9 Please help me to solve it!! Thank you!!A researcher wishes to try three different techniques to lower the blood pressure of individuals diagnosed with high blood pressure. Fifteen subjects are randomly assigned to three groups: the first group takes medication, the second group exercises, and the third group follows a special diet. Each group is assigned five subjects. After four weeks, the reduction in each person’s blood pressure is recorded. The data collected are shown in the table. Test the claim that there is no difference among means at α=0.05. Medication Exercise Diet 6 10 7 14 10 6 15 9 5 14 5 8 13 6 6 Suppose it makes sense to conduct a post-hoc analysis. We will use Tukey's test to make pairwise comparisons between means. The decision rule for Tukey's test would be as follows: "Reject H0 if |qc|>q0.05,K,L=M. Otherwise, fail to reject H0."Use the Critical Values for the Tukey Test 1. What is the value for the number of treatments, K? (2 decimals) 2. What is the value for df for error, L? (2…A researcher wishes to try three different techniques to lower the blood pressure of individuals diagnosed with high blood pressure. Fifteen subjects are randomly assigned to three groups: the first group takes medication, the second group exercises, and the third group follows a special diet. Each group is assigned five subjects. After four weeks, the reduction in each person’s blood pressure is recorded. The data collected are shown in the table. Test the claim that there is no difference among means at α=0.05. Medication Exercise Diet 6 10 7 14 10 6 15 9 5 14 5 8 13 6 6 Proceed with the computations for Tukey Test assuming that it is viable to perform a post-hoc analysis. 1. Pairwise Comparison Test 1 Given the hypotheses: H0:μ1=μ2; Ha:μ1≠μ2 Compute for the Tukey's q-statistic. (4 decimals) ______________ 2. Pairwise Comparison Test 2 Given the hypotheses: H0:μ1=μ3 ; Ha:μ1≠μ3 Compute for the Tukey's q-statistic.(4 decimals) ______________ 3. Pairwise…