A net force of 3.50N acts on an object with a mass of 2.75 kg and has a frictional force equivalent to 0.056 N. Find the system‘s acceleration with free body diagram

Please write your complete solution. Thank you! The body shown is acted on by four forces. Determine the location and magnitude of the resultant force.

A 16.2 kg box (labelled m1) rests on a table. Weight of box is 160N, and the normal force acting on it from the table is 160N. A second box m2, of mass 1.93 kg, is placed on top of the 16.2 kg box. 1. Determine the normal force (in newtons) that the table now exerts on the 16.2 kg box. 2. Determine the normal force (in newtons) that the 16.2 kg box exerts on the 1.93 kg box.

A large mass M = 9.00 kg hangs from a massless rope that is connected to a box, m = 5.00 kg. The rope passes over a massless pulley and does not stretch. Due to the hanging mass, the box is accelerated along the surface to the left.a) Draw free-body diagrams for the mass, M, and the box, m. Indicate xy-coordinate directions for each object. Indicate the direction of positive acceleration. b) If the acceleration of the box is 5.50 m/s2 determine the coefficient of kinetic friction µk between the box and the table surface.