College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A negatively charged rod of finite length carries charge with a uniform charge per unit length. Sketch the electric field lines in a plane containing the rod.
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- A very large nonconducting plate lying in the xy-plane carries a charge per unit area of 7?. A second such plate located at z = 3.10 cm and oriented parallel to the xy-plane carries a charge per unit area of −8?. Find the electric field for the following. (a) z < 0 ?/?0 (b) 0 < z < 3.10 cm ?/?0 (c) z > 3.10 cm ?/?0arrow_forwardSuppose there are two uniformly charged non-conducting spheres, one with a charge +Q, the other of charge -Q, each with radius R. The centres of these spheres are separated by a distance z = 3R. Draw a diagram indicating this, and show the positions where the electric field is equal to zero.arrow_forwardProblem 12: A uniformly charged rod of length L = 1.4 m lies along the x-axis with its right end at the origin. The rod has a total charge of Q = 8.2 μC. A point P is located on the x-axis a distance a = 1.8 m to the right of the origin. Part (a) Consider a thin slice of the rod of thickness dx located a distance x away from the origin. What is the direction of the electric field at point P due to the charge on this thin slice of the rod? Part (b) Write an equation for the electric field dE at point P due to the thin slide of the rod dx. Give your answers in terms of the variables Q, L, x, a, dx, and the Coulomb constant, k. Notice that the coordinate x will be less than zero over the length of the rod. Part (c) Integrate the electric field contributions from each slice over the length of the rod to write an equation for the net electric field E at point P. Part (d) Calculate the magnitude of the electric field E in kilonewtons per coulomb (kN/C) at point P due to the charged…arrow_forward
- In the figure a small, nonconducting ball of mass m = 1.1 mg and charge q = 2.0 × 108 C (distributed uniformly through its volume) hangs from an insulating thread that makes an angle 0 = 30° with a vertical, uniformly charged nonconducting sheet (shown in cross section). Considering the gravitational force on the ball and assuming the sheet extends far vertically and into and out of the page, calculate the surface charge density of the sheet. + + + + + + + + + + + + + O aarrow_forward1. As shown below, one plastic rod with length L and carrying a uniformly distributed charge +Q is placed on the x-axis such that one end is on the origin and the other end is on the point x = -L. Another plastic rod with length L and carrying a uniformly distributed charge -Q is placed right next to the positively charged line such that one end is on the origin and the other end is on the point x = L. Find the magnitude and direction of the electric field at a point Pa distance D away from the end of the negatively-charged rod as shown below. Express your answer in terms of Q, L, D and а. other known constants (i.e. ke). (Hint: Try using the result from an example we did in class and use superposition from the two individual rods). b. Find the magnitude and direction of the electric force of an electron placed at point P. Express your answer in terms of the above constants, as well as the fundamental charge, e. +Q X = 0 x = -L x = L Darrow_forwardThe figure below shows a dipole. If the positive particle has a charge of 36.9 mC and the particles are 2.62 mm apart, what is the electric field at point A located 2.00 mm above the dipole's midpoint? (Express your answer in vector form.)arrow_forward
- A positively charged line with linear charge density λ is pictured along the x-axis with length L. Starting with the differential form of Coulomb’s Law () derive an equation for the electric field at point P at (x=a, y=0) k, a, L, and λ.arrow_forward(a) Find the magnitude and direction of the net electric field at point P. For direction, give the angle counterclockwise from the positive x-axis. Draw the electric fields created by q1, q2 , and the net electric field in the diagram above. (b) Suppose a particle with charge -6.3 microC and mass 1.5 * 10 ^ - 27 kg, is placed at point P. Find the magnitude and direction of the acceleration of that particle. For direction, give the angle counterclockwise from the positive x-axis.arrow_forwardA small rubber sphere has a mass of 3.64 g and a charge of -18.6 µC. It levitates, motionless, when placed in a uniform electric field perpendicular to the ground. What is the magnitude of the electric field (in N/C)? N/C What is the direction of the electric field? O upward O downward O east westarrow_forward
- very long and thin insulating rod has a charge of +Q uniformly distributed along its length. The rod has a length L. Use Gauss’s lawto determine the electric field near the middle of the rod a short distance, d, from the axis of the rod.arrow_forwardA solid non-conducting sphere of radius 3 cm has a charge of +24 micro(u)C. A conducting spherical shell of inner radius 6 cm and outer radius 10 cm is concentric with the solid non-conducting sphere and carries a charge of -10 micro C. What is the force on an electron located midway in the space between the shell and the solid sphere?arrow_forwardThe figure below shows a small, charged bead, with a charge of q = +41.0 nC, that moves a distance of d = 0.174 m from point A to point B in the presence of a uniform electric field E of magnitude 255 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the bead? magnitude Ndirection (b) What is the work (in J) done on the bead by the electric force as it moves from A to B? J (c) What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead and all its surroundings.) PEB − PEA = J (d) What is the potential difference (in V) between A and B? VB − VA = Varrow_forward
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