i need help with this question and all its parts asap A mixture of propane (C3H3) and butane (C4H10) is burnt with pure oxygen gas in excess in afurnace. The stack gas was analyzed to be 47.4 mol% water vapor, 36.5 mole% CO2, and 16.1mole% of oxygen. Hint: no CO is found in the stack gas.(a) Write down all the possible chemical equation(s) taking place in the reaction system.(b) Plot a diagram illustrating the process.What is the composition of the feed gas stream (in both absolute moles and mole fractions).

Givencombustion of propane and butane with pure oxygen in excessmolar composition of stack gas , 47.4% H2O+36.5% CO2+16.1%O2To a. write down the chemical equation for all the reactions taking placeb. plot a diagram to illustrate the processc.composition of feed gas stream ( in moles and mole fractions)a. Since no CO is found in the SG, and pure O2 is fed to the combustion process,the following complete combustion reactions of propane and butane are taking placeC3H8(g)+5O2(g)→3CO2(g)+4H2O(g) reaction 12C4H10(g)+13O2(g)→8CO2(g)+10H2O(g) reaction 2b.c. composition of feed gas streamThe underlying reactions areC3H8(g)+5O2(g)→3CO2(g)+4H2O(g) reaction 12C4H10(g)+13O2(g)→8CO2(g)+10H2O(g) reaction 2 Taking 100 mol of stack gas as basis, its molar composition isH2O=47.4 molesCO2=36.5 molesO2=16.1 molesThese moles of CO2 are generated from reactions 1 and 2 in the ratios as followsRatio of CO2 generated from reaction 1=moles of CO2 from reaction 1moles of CO2 from reaction 1+moles of CO2 from reaction 2=33+8=311Ratio of CO2 generated from reaction 2=moles of CO2 from reaction 2moles of CO2 from reaction 1+moles of CO2 from reaction 2=83+8=811Reaction 1 moles of CO2 entering SG =311×36.5=9.95 molmoles of C3H8 reacting=13×9.95 =3.316 moltheoretical moles of O2 reacting=53×9.95 =16.58 molReaction 2moles of CO2 entering SG =811×36.5=26.54 moltheoretical moles of C4H10 reacting=28×26.54=6.635 mol moles of O2 reacting=138×26.54 =43.1275 molThe total moles of constituents in feed gas stream = moles of propane+moles of butane+theoretically required moles of oxygen from rxn 1 +theoretically required moles of oxygen from rxn 2+excess moles of oxygen in SG=3.316+6.635+16.58+43.1275+16.1 =69.658 molMole fraction of feed stream gasesC3H8=moles ofC3H8Total number of moles=3.316 mol69.658 mol=0.0476, or 4.76%C4H10=moles of C4H10Total number of moles=6.635 mol69.658 mol=0.09525, or 9.52%O2=theoretical moles of O2+excess moles of O2Total number of moles=16.58+43.1275 mol69.658 mol=0.857152, or 85.71 %