A mixture of 8.05 moles of A, 10.36 moles of B, and 27.16 moles of C is placed in a one-liter container at a certain temperature. The reaction is allowed to reach equilibrium. At equilibrium the number of moles of B is 17.63. Calculate the equilibrium constant for the reaction: A (g) + 2 B (g) - 3 C (g) Hint: Apply RICE method. R-reaction: aA + bB + CC + dD |-initial concentration: 0 0 C-Change: -X -X E-equilibrium concentration: +X -X

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A mixture of 8.05 moles of A, 10.36 moles of B, and 27.16
moles of C is placed in a one-liter container at a certain
temperature. The reaction is allowed to reach
equilibrium. At equilibrium the number of moles of B is
17.63. Calculate the equilibrium constant for the
reaction:
A (g) + 2 B (g) - 3 C (g)
Hint: Apply RICE method.
R-reaction:
aA + bB + CC + dD
l-initial concentration:
C-Change:
-X
-X
E-equilibrium concentration:
+X
+X
-X
Transcribed Image Text:A mixture of 8.05 moles of A, 10.36 moles of B, and 27.16 moles of C is placed in a one-liter container at a certain temperature. The reaction is allowed to reach equilibrium. At equilibrium the number of moles of B is 17.63. Calculate the equilibrium constant for the reaction: A (g) + 2 B (g) - 3 C (g) Hint: Apply RICE method. R-reaction: aA + bB + CC + dD l-initial concentration: C-Change: -X -X E-equilibrium concentration: +X +X -X
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