A medical researcher wants to investigate the amount of time it takes for patients' headache pain to be relieved after taking a new prescription painkiller. She plans to use statistical methods to estimate the mean of the population of relief times. She believes that the population is normally distributed with a standard deviation of 24 minutes. How large a sample should she take to estimate the mean time to within 3 minutes with 92% confidence? Sample Size =

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A: Boxplot in the given question.

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A: Given that the distribution is normal.Sample size (n) = 37Sample mean () = 12.15Standard deviation…

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A: The probability shows how likely an event occurs.

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A: Sample sizes n1=35 ,n2=50Sample means x1=25.4 ,x2=23.3

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A:

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A: Number of independent variable =5Number of observation=10We have to find the degree of freedom:

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A: Hello! As you have posted more than 3 sub-parts, we are answering the first 3 sub-parts.  In case…

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A: 5C5Determine the combination

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A: Sample size n=64Sample mean=43500Standard deviation=6800

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A: Mean()=3.2 yearsStandard deviation()=0.9 years

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A: From the provided information,n = 50x = 35Confidence level = 90%

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A: The of a standard normal distribution is 0 and the  is 1.

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A: Z has follows standard normal distribution with mean zero and standard deviation one.

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A: From the provided information,Sample size (n) = 4Confidence level = 95%

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A: A 3 by 3 chi-square.

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A: Number of trail n=3Probability of success p=0.92

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A: n=8, s=16, X¯=315

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A: Mean()=100Standard deviation()=15sample size(n)=36

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A: X~Exp(λ=150=0.02)

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A: 2.3, 1.0, 2.1, 6.5, 2.8, 7.8, 1.7, 2.9, 4.4, 5.1, 2.0

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A: It is given that n = 20s = 0.23Confidence level = 80%

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A: Significance level is increasedAnswer and expaination is provided below

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A: Z has follows standard normal distribution with mean zero and standard deviation one.

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A: Comment: As per the our company guidelines we are supposed to answer only three subparts. Kindly…

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A: Normal distribution