A measuring instrument has a 0.5% error, that is, if a length measures 100mm, it has an error of ±0.5mm. The radius of a sphere is measured with such instrument as 65mm. Calculate (to the closest mm³) the Volume of this sphere? Volume = Using the "small change formula", calculate (to the closest mm³) the approximate change in the Volume = ± mm³ What is the percentage error (to one decimal place) in the Volume given the formula below? The percentage error in the volume ΔΙ' mm³ R -x 100 % %

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