A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 8 inches below the equilibrium position.(a) Find the position x of the mass at the times t = 1/12, x/8, n/6, n/4, and 97/32 s. (Use g = 32 ft/s2 for the acceleration due to gravity.)x(1/12) = 0.666X ftX(x/8) = 0.666X ftx(x/6) = 0.665X ftx (π/4)0.663X ft=x(9л/32)0.662X ft(b) What is the velocity of the mass when t = 3x/16 s?16ft/s3In which direction is the mass heading at this instant?upwarddownward(c) At what times does the mass pass through the equilibrium position?164X , n = 0, 1, 2, . A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 8 inches below the equilibrium position.(a) Find the position x of the mass at the times t = n/12, n/8, n/6, a/4, and 97/32 s. (Use g = 32 ft/s? for the acceleration due to gravity.)X(1/12) =-0.33X ftx(x/8) =-0.66X ftx(л/6) %3-0.33X ftx(T/4) =0.66X ftx(9x/32) =0.47X ft(b) What is the velocity of the mass when t = 37/16 s?16ft/s3In which direction is the mass heading at this instant?upwarddownward(c) At what times does the mass pass through the equilibrium position?164X , n = 0, 1, 2,+

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A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 8 inches below the equilibrium position. (a) Find the position x of the mass at the times t = r/12, n/8, 1/6, x/4, and 97/32 s. (Use g = 32 ft/s2 for the acceleration due to gravity.) x(7/12) = 0.666 X ft x(x/8) = 0.666 X ft x(x/6) = 0.665 X ft x(x/4) = 0.663 X ft x(9x/32) = 0.662 X ft (b) What is the velocity of the mass whent = 37/16 s? 16 3 ft/s In which direction is the mass heading at this instant? upward o downward (c) At what times does the mass pass through the equilibrium position? + 16 X , n = 0, 1, 2, ...

A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 8 inches below the equilibrium position. (a) Find the position x of the mass at the times t = r/12, n/8, 1/6, x/4, and 97/32 s. (Use g = 32 ft/s2 for the acceleration due to gravity.) x(7/12) = 0.666 X ft x(x/8) = 0.666 X ft x(x/6) = 0.665 X ft x(x/4) = 0.663 X ft x(9x/32) = 0.662 X ft (b) What is the velocity of the mass whent = 37/16 s? 16 3 ft/s In which direction is the mass heading at this instant? upward o downward (c) At what times does the mass pass through the equilibrium position? + 16 X , n = 0, 1, 2, ...

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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