A mass of 6 kg stretches a spring 24 cm. The mass is acted on by an external force of 5 sin() N (newtons) and moves in a medium that imparts a viscous force of 12 N when the speed of the mass is 4 cm/s. If the mass is set in motion from its equilibrium position with an initial velocity of 10 cm/s, formulate the initial value problem describing the motion of the mass. Assume that g = 9.8 m 6 +12 +2.45u Ssin( () 10 6 +300+245u=5sin( (). 10 6u" + 300u +245u Ssin( 6u" + 300u' +2.45u = 5sin() 6 + 12 +245u = 5sin(). (0) = 0, / (0) = 0.10, (0) = 0.10, 1/(0) = 0. uin meters. uin meters. (0) = 0, (0) 0.10, in meters. (0) = 0, / (0) = 0.10, (0) = 0, 1/(0) = 0.10, uin meters. uin meters.

A mass of 6 kg stretches a spring 24 cm. The mass is acted on by an external force of 5 sin() N (newtons) and moves in a medium that imparts a viscous force of 12 N when the speed of the mass is 4 cm/s. If the mass is set in motion from its equilibrium position with an initial velocity of 10 cm/s, formulate the initial value problem describing the motion of the mass. Assume that g = 9.8 m 6 +12 +2.45u Ssin( () 10 6 +300+245u=5sin( (). 10 6u" + 300u +245u Ssin( 6u" + 300u' +2.45u = 5sin() 6 + 12 +245u = 5sin(). (0) = 0, / (0) = 0.10, (0) = 0.10, 1/(0) = 0. uin meters. uin meters. (0) = 0, (0) 0.10, in meters. (0) = 0, / (0) = 0.10, (0) = 0, 1/(0) = 0.10, uin meters. uin meters.

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

A mass of 6 kg stretches a spring 24 cm. The mass is acted on by an external force of 5 sin() N (newtons) and moves in a medium
that imparts a viscous force of 12 N when the speed of the mass is 4 cm/s. If the mass is set in motion from its equilibrium position
with an initial velocity of 10 cm/s, formulate the initial value problem describing the motion of the mass. Assume that g = 9.8
6" + 12 +2.45u = 5sin(
6 +300+245u=5sin(
6u" + 300u' +245u = 5sin().
6" + 300 +2.45u = 5sin().
6 + 12
(0) = 0, / (0) = 0.10, in meters.
(0) = 0.10,
(0) = 0,
uin meters.
(0) = 0,
(0) = 0.10,
uin meters.
(0) = 0.
(0) = 0.10,
win meters.
+245u = 5sin(). (0) = 0, 1/(0) = 0.10, uin meters.
n().
10

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