A mass ma = 3.0 kg , moving with velocity VA = (5.0i + 5.4j- 2.0k) m/s, collides with mass mB = 3.4 kg , which is initially at rest. Immediately after the collision, mass ma = 3.0 kg is observed traveling at velocity VA = (-2.0i + 3.2k) m/s. Part A Find the velocity of mass mB after the collision. Assume no outside force acts on the two masses during the collision. Enter the x, y, and z components of the velocity separated by commas. Express your answer to two significant figures. Πν ΑΣφ ?

Two manned satellites approaching one another at a relative speed of 0.100 m/s intend to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. Assume that the positive direction is directed from the second satellite towards the first satellite. (a) Calculate the final velocity after docking, in the frame of reference in which the first satellite was originally at rest.m/s(b) What is the loss of kinetic energy in this inelastic collision?J(c) Repeat both parts, in the frame of reference in which the second satellite was originally at rest.final velocitym/sloss of kinetic energyJ

An unstable particle is at rest and suddenly breaks up into two fragments. No external forces act on the particle or its fragments. One of the fragments has a velocity of +0.837c and a mass of 1.77 × 10-27 kg, and the other has a mass of 5.29 × 10-27 kg. What is the velocity of the more massive fragment (as a multiple of c)? (Hint: This problem is similar to Example 6 in Chapter 7.) Unstable particle at rest Number i V2 m2 Units m1 V1 Recoiling fragments

Two manned satellites approaching one another, at a relative speed of 0.200 m/s, intending to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg.   a. Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was originally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answer.)  m/s   b. What is the loss of kinetic energy (in J) in this inelastic collision?  J   c. Repeat both parts by using the frame of reference in which the second satellite was originally at rest. final velocity (m/s) m/sloss of kinetic energy (J) J   Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.

In 1977 the planet Alderaan, with a mass of 3 x 1024 kg, exploded. Assuming it was initially at rest and experienced no external interactions, 3. A) If the planet blew apart into two pieces with 40% of its mass flying away in one piece at 4,000 km/s, what speed did the rest of the planet have relative to its original frame? B) If the planet blew apart into three pieces, with 30% of its mass flying away at 3,000 km/s, and 20% of its mass flying away at 5,000 km/s at an angle of 120° relative to the velocity direction of the first fragment, what velocity did the rest of the planet have? Report the direction by specifying its angle relative to the velocity direction of the first fragment.

An unstable particle is at rest and suddenly breaks up into two fragments. No external forces act on the particle or its fragments. One of the fragments has a velocity of +0.811c and a mass of 1.57 × 10-27 kg, and the other has a mass of 5.98 × 10-27 kg. What is the velocity of the more massive fragment (as a multiple of c)? (Hint: This problem is similar to Example 6 in Chapter 7.) Unstable particle at rest V2 m2 m1 V1 Recoiling fragments

The carbon isotope 14C is used for carbon dating of objects.  A  14C nucleus can change into a different kind of element, a neighbor on the periodic table with lower mass, by emitting a beta particle – an electron or positron – plus a neutrino or an anti-neutrino.  Consider the scenario where 14C ( mass of 2.34 x 10 -26) decays by emitting an electron and anti neutrino.  The electron has a mass of 9.11x 10-31 kg and a speed of 5.5 x107  m/s.  While the anti neutrino has  a momentum of 8.5x10-24 kg-m/s.  If the electron and anti neutrino are emitted at right angles from each other, calculate the recoil speed of the nucleus.

A 212^Bi (bismuth) nucleus undergoes alpha decay, resulting in a 208^Tl (thallium) nucleus and a 4He (helium) nucleus as per the following reaction: 212^Bi →208^Tl + 4^He The masses of each nucleus is listed in the table below. Given that the bismuth atom was at rest before the reaction, if the resulting thallium nucleus is traveling 3.3 × 105 m/s, how fast is the helium nucleus traveling?

An electron-positron collider creates muons through the reaction et +e →µ* +µ. In the center-of-momentum frame, what is the minimum speed of the electron for this reaction to occur, in terms of the masses me and mu of the electron and muon? Oc(1-) 2m 7ne - my O This process can occur at any speed.

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