A mass is on an inclined plane with a length of 4 m and an angle of 30 degrees; the friction coefficient between the mass and the inclined plane is 0.25. The mass is initially halfway up the inclined plane and is thrown downward. What will be its speed at the bottom of the inclined plane and how much will it compress a spring (spring constant 100 N/m) which is just at the bottom of the inclined plane if we have a friction coefficient of 0.3 between the mass and the horizontal table where the spring rests? (Let's assume that the mass is 3 kg)

A sled is initially given a shove up a frictionless 26.0 incline. It reaches a maximum vertical height 1.50 m higher than where it started at the bottom. a) What was its initial speed?

A box is pressed against a horizontal spring, compressing the spring from its relaxed length. The box is then released and the spring launches the box horizontally along a track that ends in a ramp, as shown above. The box has enough speed to leave the ramp, and the box reaches a maximum vertical height above the floor. Assume there is negligible friction between the box and the track and air resistance is negligible.   K = spring constant of spring X = distance the spring is compressed M = mass box Theta = angle of ramp from horizontal H = maximum height reached by box   The scenario is repeated using a different box with a greater mass. The spring is compressed the same distance x.   Indicate how h in this second scenario compares to h in the original scenario, and explain why without mathematically deriving a relation for h. Students derive an equation for h in the original scenario, h= (sin2theta)kx2/2Mg, which may or may not be correct. Is this equation consistent with your claim…

A certain spring is found not to obey Hooke's law; it exerts a restoring force F(x) = -ax² - 6x³ if it is stretched or compressed, where: a = 10.0N/m², B = 300.0N/m³ The mass of the spring is negligible. Calculate the potential energy function U(x) for this spring, if U(x=0) = 0. Find the spring potential energy at x = 0.500 m

A particular spring on the Earth is found to have a spring constant of k = 1400 N/m. If the same spring is taken to Marsa. The spring constant will be less than on Earthb. The spring constant will be the same as on Earthc. The spring constant will be more than on Earthd. Springs do not work on Marse. We cannot answer this question because we cannot get a spring to Mars

On Earth with a gravational acceleration g, the potential energy stored in an object varies directly with its mass m and its vertical height h. What is the equations of the potential energy of a 2kg skateboard that is sliding down a ramp?

(Figure 1) depicts the potential energy of a 660-kg pallet that slides from rest down a frictionless roller conveyer ramp, then moves across a frictionless horizontal conveyer, and finally encounters a horizontal spring at x=4.0m. What is the angle of inclination of the conveyer ramp? What will be the speed of the pallet at x=6.0m if it begins sliding from rest at x=0?

A box with 14 kg of mass slides down an inclined plane that is 1.8 m high and 3.9 m along the inclined plane. Due to friction the box reaches 4.6 m/s at the bottom of the inclined plane. Beyond the inclined plane lies a spring with 750 N/m constant. It is fixed at its right end. The level ground between the incline and the spring has no friction When the box is temporarily stopped by the spring, how much is the spring compressed in m? Hint: start from the bottom of the inclined plane since you know the speed of the box there. Not all values must be used.