A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be š = $14.50 . Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50 . To address the CEO's conjecture, the marketing manager carried out a test of the hypothesis Họ : µ = 13.50 vs. Ha : µ > 13.50 and obtained a P-value of p = 0.077.

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A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of
lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey
of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be i = $14.50 . Based on
previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50 . To address the
CEO's conjecture, the marketing manager carried out a test of the hypothesis Ho : u = 13.50 vs. H. : µ > 13.50 and
obtained a P-value of p = 0.077.
This result is significant at:
a = 0.01 .
O a = 0.05 .
O a = 0.02.
O a = 0.1 .
Transcribed Image Text:A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be i = $14.50 . Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50 . To address the CEO's conjecture, the marketing manager carried out a test of the hypothesis Ho : u = 13.50 vs. H. : µ > 13.50 and obtained a P-value of p = 0.077. This result is significant at: a = 0.01 . O a = 0.05 . O a = 0.02. O a = 0.1 .
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