"A manufacturer of shampoo claims that 72% of the shampoo users prefer brand X. To test this claim, a random sample of 44 participants are selected and asked what brand they prefer. If 31 of the 44 participants prefer brand X, what conclusion do we draw? Use a 0.1 level of significance. What are the given? hypothesized proportion:Blank 1% sample proportion:Blank 2 (Write your answer in fraction form form and simplify your answer) sample size:Blank 3 level of significance:Blank 4 What are the critical values? Write the positve first then the negative z:Blank 5 andBlank 6 What is the calculated z? Round your answer to the nearest hundredths. z:Blank 7"

In a Gallup poll of 1236 adult respondents, 6% said that bad luck follows breaking a mirror. That percentage has a margin of error of 1.5 percentage points. Why is it misleading to state that the percentage is 6% with a margin of error of 1.5%?

"Suppose that in the past, 47% of all adults favored capital punishment. Do we have a reason to believe that the proportion of adults favoring capital punishment today has increased if, in a random sample of 58 adults, 37 favor capital punishment? Use a 0.05level of significance. What are the given? hypothesized proportion:Blank 1% sample proportion:Blank 2 (Write your answer in fraction form and simplify) sample size:Blank 3 level of significance:Blank 4 What is the critical value? z:Blank 5 What is the calculated z? Round your answer to the nearest hundredths. z:Blank 6"

The sample mean is the point estimator of а. O b. o О с. р С. O d. H

Statistics Canada conducts an annual survey to estimate the proportion of Canadians aged 20 - 24 years of age who are smokers. The most recent application of the Canadian Tobacco Monitoring Survey involved a random sample of n=496 Canadians aged 20 to 24 years of age. Each was asked for the smoking status. The number of 20 to 24 year-olds sampled who indicated they were smokers was 333.(a) Compute the sample proportion. Use at least four decimals in your answer.p^= __________ (b) Using your answer in (a), find a 97% confidence interval for pnow, the current proportion of 20 to 24 year old Canadians who are smokers, by Bootstrapping 1000 samples. Use the seed 3994 to ensure that R-Studio "randomly" samples the same "random" samples as this question will expect.You can do this by including the code, you can copy it into your R-Studio to bootstrap your samples.RNGkind(sample.kind = "Rejection");set.seed(3994);B=do(1000) * mean(resample(c(rep(1,333),rep(0,496-333)), 496));Use at least four…

b) Distribution of the Sample Proportion To assess attitudes towards issues that affect the residents of a village, the village randomly chose 800 families to participate in a survey of life attitudes. The village received 628 completed surveys. What is the sample proportion of completed surveys?

The first pic is the question, since I’ve been receiving some incorrect answers from the tutors, I included an example problem in the second pic.

The sample mean is the point estimator of O A. u О В. р O C. X O D. o

online customer service is a key element to successful online retailing. According to a marketing survey, 37.5% of online customers take advantage of online customer service. Random samples of 150 customers are selected. The standard error of all possible sample proportion is?