A man stands in front of a vertical plane mirror, as shown in the figure. His eyes are 1.6 m above the floor and the top of his head is 0.13 m higher than that. (a) Find the height above the floor, in meters, of the bottom edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted hb in the figure.  (b) Find the height above the floor, in meters, of the top edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted ht in the figure.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A man stands in front of a vertical plane mirror, as shown in the figure. His eyes are 1.6 m above the floor and the top of his head is 0.13 m higher than that.

(a) Find the height above the floor, in meters, of the bottom edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted hb in the figure. 

(b) Find the height above the floor, in meters, of the top edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted ht in the figure. 

h.
Transcribed Image Text:h.
Expert Solution
Step 1: The ray diagram for the question.

The distance of the bottom of the mirror is equal to half of the total height from the ground.

Physics homework question answer, step 1, image 1

QS=PS2=1.6 m2QS=0.8 m

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