A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that their satisfaction rating is 84%. Jennie, a food critic, would like to test this. She takes a sample of 129 patrons, and gets a 79.1% sample satisfaction rating. (a) Create an 80% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.) (b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 84%? O Since the interval contains 84%, Jennie should reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval contains 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should reject the null hypothesis at a = 0.2.

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A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their
meal, and the restaurant claims that their satisfaction rating is 84%. Jennie, a food critic, would like to test this. She takes a
sample of 129 patrons, and gets a 79.1% sample satisfaction rating.
(a) Create an 80% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not
percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.)
(b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 84%?
O Since the interval contains 84%, Jennie should reject the null hypothesis at a = 0.2.
O Since the interval does not contain 84%, Jennie should not reject the null hypothesis at a = 0.2.
O Since the interval contains 84%, Jennie should not reject the null hypothesis at a = 0.2.
O Since the interval does not contain 84%, Jennie should reject the null hypothesis at a = 0.2.
Transcribed Image Text:A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that their satisfaction rating is 84%. Jennie, a food critic, would like to test this. She takes a sample of 129 patrons, and gets a 79.1% sample satisfaction rating. (a) Create an 80% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.) (b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 84%? O Since the interval contains 84%, Jennie should reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval contains 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should reject the null hypothesis at a = 0.2.
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