A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that their satisfaction rating is 84%. Jennie, a food critic, would like to test this. She takes a sample of 129 patrons, and gets a 79.1% sample satisfaction rating. (a) Create an 80% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.) (b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 84%? O Since the interval contains 84%, Jennie should reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval contains 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should reject the null hypothesis at a = 0.2.

Twenty-nine college students, identified as having a positive attitude about Mitt Romney as compared to Barack Obama in the 2012 presidential election, were asked to rate how trustworthy the face of Mitt Romney appeared, as represented in their mental image of Mitt Romney’s face. Ratings were on a scale of 0 to 7, with 0 being “not at all trustworthy” and 7 being “extremely trustworthy.” Here are the 29 ratings:  2.6 3.2 3.7 3.3 3.4 3.6 3.7 3.8 3.9 4.1 4.2 4.9 5.7 4.2 3.9 3.2 4.5 5.0 5.0 4.6 4.6 3.9 3.9 5.3 2.8 2.6 3.0 3.3 3.7   a 95% confidence interval for the mean rating. Is there significant evidence at the 5% level that the mean rating is greater than 3.5 (a neutral rating)?

A new fertilizer was applied to the soil of 276 bean plants. 24% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to

A new fertilizer was applied to the soil of 246 bean plants. 25% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage):Confidence Interval: % to %

. In a random sample of 400 private high school students, 320 said they brought a smartphone to school that day, while in a random sample of 400 public high school students, 288 said they brought a smartphone to school that day. Which of the following represents a 98 percent confidence interval estimate for the difference (private high school minus public high school) between the proportions of all private high school and public high school students who bring a smartphone to school? (0.8)(0.2) (0.72)(0.28) (A) (0.8-0.72)±1.96, 400 400 (B) (0.8-0.72)±2.054, + (0.8)(0.2) (0.72)(0.28) 400 400 (C) (0.8-0.72)±2.326 + (0.8)(0.2) (0.72)(0.28) 400 400 1 (D) (0.8-0.72)±2.054, (0.76)(0.24) + 400 400 (E) (0.8-0.72)±2.326, (0.76)(0.24) + I 400 400

Last year over 7000 students took an entrance exam at a certain state university. Kareem's score was at the 44th percentile. Lella's score was at the 93rd percentile. (a) Which of the following must be true about Kareem's and Leila's scores? Both Kareem and Leila scored higher than the median. O Both Kareem and Lella scored below than the median. O Leila scored higher than Kareem. O Kareem scored higher than Leila. (b) Which of the following must be true about Kareem's score? O About 44% of the students who took the exam scored lower than Kareem. O Kareem got about 44% of the questions correct. O Kareem's score was in the top half of all scores. O Kareem missed 56 questions. Explanation Check X 3 Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center

If two people used the same data and one person made a 90% confidence interval and the other person made a 95% confidence interval for p, which interval would be more narrow?   is it; a. The 90% Confidence interval b. The 95% Confidence interval c. We cannot tell from the information alone.

Name: Statistics 1. An investigative reporter contacts a random sample of hotels, and finds a 95% confidence interval for the proportion of hotels in the United States that have reported having bedbugs is (0.04, 0.11). a. Interpret this confidence interval in context. F3 80 b. A national hospitality organization had reported that only 5% of hotels have experienced problems with bedbugs. Does this reporter have compelling evidence that the true proportion is really higher? Explain. c. How could the reporter estimate this proportion with a smaller margin of error? a. Identify the parameter, p, 2. To estimate how often someone runs a red light in Cyber City, a student watched traffic for a while at several randomly selected intersections. Drivers ran the red light during 43 of 240 light changes she observed. Q O Period: Quiz (ch 16+17) F4 9 F5 Page 1 / 2 c F6 8 + F7 Date: : DII F8 DD F9

A new fertilizer was applied to the soil of 292 bean plants. 44% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval:            %  to           %

A college in the northeastern United States used SAT scores to help decide which applicants to admit. To determine whether the SAT was useful in predicting success, the college examined the relationship between SAT scores and first – year GPAs of admitted students. Below is a table with the data collected.  (a) What would you predict the GPA to be for a student whose Math SAT score is 650? (b) What process of prediction did you use for part (a) ? Is this a good prediction? (c) What would you predict the GPA to be for a student whose Math SAT score is 725? (d) What process of prediction did you use for part (b)? Is this a good prediction? Math SAT Scores First – Year GPAs 509 2.6 471 2.3 700 2.4 719 3 710 3.1 643 2.9 665 3.1 719 3.3 693 2.3 701 3.3 614 2.6 557 3.3 611 2 701 3