A load of 425 kN/m is carried on a strip footing 2m wide at a depth of 1m in a stiff clay of saturated unit weight 21kN/m3 , the water table being at ground level. Determine the factor of safety with respect to shear failure: (a) when c u = 105 kN/m2 and Φu= 0  (b) when c=10 kN/m2 and Φ= 28 degree

Q: A load of 425 kN/m is carried on a strip footing 2 m wide at a depth of 1 m in a stiff clay of…

A: Given : Load = 425 kN/m Width of strip footing = 2 m depth of strip footing = 1 m Saturated unit…

Q: A rectangular footing 3 × 2 m with 0.5 m thickness is under a column 420 × 420 mm. It is subjected…

A: Given: Dimensions of footing = 3 x 2 m Thickness of footing = 0.5 m Dimensions of column = 420 x 420…

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A: The unit weight of the concrete is γ=23.5 kN/m3.

Q: A strip footing was constructed on a pure sand which is 1.5 m wide with its base at a depth of 1 m.…

A: Given -  Width = 1.5 m Depth = 1 m Yd = 16 kN/m3 Ny = 75 To find -  The bearing capacity of strip…

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Q: . It was speculated that failure occurred by bearing capacity failure. Clarify whether this is so or…

A: Ultimate bearing capacity using general bearing capacity equation is given by qu=c'Ncscicdc+…

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Q: A strip footing 1.5 m wide is located at a depth of 0.75 m (equal to the foundation thickness) in a…

A: Width of strip footing = 1.5m , Depth = 0.75m = Thickness of foundation , Unit weight of sand =…

Q: Calculate the width of footing required

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Q: Q3) A 2 mx 3 m spread footing placed at a depth of 1.75 m on a clayey sand soil with a unit weight…

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Q: Calculate the factor of safety of a square footing with a moment in one axis. Use Terzaghi’s…

A: Terzaghi's Bearing Capacity Theory : According to Terzaghi's Bearing Capacity Theory, a foundation…

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Q: A load of 430 kN/m is carried on a strip footing 2m wide at a depth of Im in a stiff clay of…

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Q: a) Find the allowable load on the foundation by Terzaghi method, assuming a general shear failu with…

A: Answer Net allowable load = Qall  Cohesion C =13 kpa Dry Unit weight of soil (γd) =17 Kn/m3…

Q: Given: a 0.3 m b = 0.6 m c = 0.6 m d = 3.5 m e = 5 m f = 0.5 m Soil unit weight = 17 kN/m3 Concrete…

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Q: Question Attached

A: Given:-γsat=18.5kN/m3w=22%q=100kN/m220mdry sand =3mGs=2.70Cc=0.30Size = 20m x 20mγ=17.5kN/m3To…

Q: Question attached

A: Solution Given Data c1=0c2=0γ1= 18 kN/m3γ2=16.7 kN/m3

Q: ompute the total vertical stress incre

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Q: 7. [Soil Bearing Capacity] a gross load of 700 kN. Using a factor of safety 3, determine the…

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Q: rectangular footing 3 × 2 cted to a moment of 90 kNm

A: Given data Rectangular footing= 3×2m Column=420×420mm E=21×103kN/m2 μ=0.3

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A: This question is related to Foundation from Soil Mechanics.

Q: Recompute factor of safety against sliding at Point A based on the underlying soil being clay. Still…

A: c'= 300 psfsu= 700 psfShear stress = 400psf

Q: Q2: A square footing (2x2 m) is constructed on a sandy soil as shown below. Find the maximum…

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Q: KN The square footing below is built on saturated sand with Ysat = 20 and Ø' = 30°. If the…

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Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.