College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Three capacitors of capacitance C1 1.35 иF, С2 %3 3.95 иF, and Сз 4.20 µF are connected in series. A potential difference of AVb 94.0 V is maintained by a battery. Find the equivalent capacitance of the series of capacitors and the charge on each capacitor. Сед Did you accidentally divide or take the inverse in your calculation? µF µC Determine the effect on the equivalent capacitance of reducing the second capacitance to 0.1 times its previous value. Ceq = HFarrow_forwardA cylindrical capacitor having a radius of 2.6 cm and 3.0 cm for positive and negative conductor respectively. If the charges on each conductor are 950nC, what is the voltage across the capacitor if the length of capacitor is 5.0 cm? Please show solutions!arrow_forwardProblem 7: Capacitor C, is initially charged to V, and capacitor C, is initially charged to V. The capacitors are then connected to each other, positive terminal to positive terminal and negative terminal to negative terminal. If C = 16 µF with initial voltage of 25 V, and capacitor C2 = 13 µF is charged to 7 V. What is the final voltage, in volts, across C;? V =arrow_forward
- What is the voltage across the plates of the capacitor if the capacitance is 10 uF and the Charge stored is 30 uC?arrow_forwardPart A:Find the load on the first capacitor.Express your answer in terms of C and V1. Part B:Using the calculated Q value, find the equivalent capacitance for these capacitors connected in series.arrow_forwardSuppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rb has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = ae-r/ao + B/r + bo where alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by: Vab = Edr Edr Calculating the antiderivative or indefinite integral, Vab = (-aager/a0 + B + bo By definition, the capacitance C is related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C= Q/( (e-rb/ao - eTa/ao) + ß In( ) + bo ( ))arrow_forward
- Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius rg has a charge of +Q, while the outer cylinder of radius rp has charge-Q The electric field E at a radial distance r from the central axis is given by the function: E = ae rlao + B/r + bo where alpha (a), beta (8), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by: Vob = Fdr = - Edr Calculating the antiderivative or indefinite integral, Vab = (-aage r/ao + p bo By definition, the capacitance C is related to the charge and potential difference by: Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q/( (eTb/ao - eTala0) + B In( )+ bo (arrow_forwardSuppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius ry has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = aer/a0 + B/r + bo where alpha (a), beta (8), an and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vah between the two conductors. The potential difference is related to the electric field by: Vah = Edr= - Fdr Calculating the antiderivative or indefinite integral, Vab = (-aager/a0 +8 + bo By definition, the capacitance Cis related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C= Q/( (e"b/a0 .eralao) + B In( )+ bo ( ))arrow_forwardCylindrical conducting surfaces with relative permittivity of 390 are used as plates of a capacitor. It has a thickness of 3.24 mm and a radius of 4.6 cm. What is the energy stored in this capacitor if a voltage of 362 V is applied?arrow_forward
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