A light ray in air (n = 1.00) hits turpentine (n = 1.47) at an angle of 35° to the surface. Determine the angle of refraction.

Air has an index of refraction of 1.00. Water has an index of refraction of 1.33. Consider a pool of water that is perfectly calm and 3.21 meters deep. A ray of light (or a laser beam, if you like) enters the water, refracts, and ultimately hits the bottom of the pool. Find the distance between the point where the light enters the water and the point where the light hits the bottom of the pool if the angle between the ray in air and the surface of the pool is 46.4 degrees. Answer in meters.

A ray of light crosses the boundary between some substance with n = 1.54 and air, going from the substance into air. If the angle of incidence is 29◦ what is the angle of refraction?   Calculate to 1decimal.

Using filters, a physicist has created a beam of light consisting of three wavelengths: 400 nm (violet), 500 nm (green), and 650 nm (red). She aims the beam so that it passes through air and then enters a block of crown glass. The beam enters the glass at an incidence angle of  ?1 = 31.5°. The glass block has the following indices of refraction for the respective wavelengths in the light beam. wavelength (nm) 400 500 650 index of refraction n400 nm = 1.53 n500 nm = 1.52 n650 nm = 1.51 (a) Upon entering the glass, are all three wavelengths refracted equally, or is one bent more than the others?   (b) What are the respective angles of refraction (in degrees) for the three wavelengths? (Enter each value to at least two decimal places.) (i) ?400 nm   (ii) ?500 nm   (iii) ?650 nm

In the figure, light is incident at angle θ1 = 37˚ on a boundary between two transparent materials. Some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air. If n1 = 1.26, n2 = 1.42, n3 = 1.32 and n4 = 1.45, what is the value of (a) θ5 and (b) θ4?

A ray of light hits the surface between air and an unknown material at an angle A of 58.8°. It travels through the unknown material at an angle B of 38.5° relative to the vertical. What is the index of refraction of the material?

Problem 13: A ray of light is incident on an air/water interface. The ray makes an angle of 01 = 22 degrees with respect to the normal of the surface. The index of the air is n = 1 while water is n₂ = 1.33. Part (b) Numerically, what is the angle in degrees? 0₂=1 Part (a) Choose an expression for the angle (relative to the normal to the surface) for the ray in the water, 02. Answer Saved Successfully! 8₂=asin (sin()) sin() cos() cotan() asin() atan() acotan() cosh() sinh() tanh() cotanh() Degrees O Radians Submit tan() acos() E 4 5 6 1 2 3 () Hint * Feedback 7 8 9 HOME 1 + 0 VO BACKSPACE DEL CLEAR - I give up! . ni END n2 0₁ 02₂

In the figure, light is incident at angle 8₁ = 39° on a boundary between two transparent materials. Some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air. If n₁ = 1.28, n₂ = 1.38, n3 = 1.34 and n4 = 1.45, what is the value of (a) 05 and (b) 04? 18₁ Air m n₂ 173 na

A light ray in glass (refractive index 1.57) arrives at the glass-water interface at an angle of 0 = 48° with the normal. The index of refraction of water is 1.33. What is the angle of refraction @ that a refracted ray makes with the normal ? water glass O 42° O 56° O 61° O 20°