A LED lamp is used to do Young’s double slit interference experiment. The slit separation d = 0.02 mm. On the screen behind, it is found that the distance between first order maximum of green light (532 nm) and second order minimum of red light (643 nm) is Δy =15 cm. Find the distance between slit and screen S.

In a two-slit experiment, the slit separation is 2.00 × 10^-5m. The interference pattern is recorded on a flat screen-like detector that is 2.00 m away from the slits. If the seventh bright fringe on the detector is 16.0 cm away from the central fringe (fringe zero), what is the wavelength of the light passing through the slits?

In an experiment using Young's slits, the distance between the center of the interference pattern and tenth bright fringe on either side of it is 3.44 cm and the distance between the slits and the screen is 2.0 m. If the wavelength of light used is 5.89x10-7m, determine the slits separation.

Light is sent through a single slit of width w = 0.52 mm. On a screen, which is L = 1.9 m from the slit, the width of the central maximum is D = 5.2 mm. a) The angle of the first dark fringe theta dark. Express sin(theta dark) in terms of the wavelength of the light λ and w. sin(theta dark) =  b) Express tan(theta dark) in terms of D and L. c) If D << L, how is tan(theta dark) related to sin(theta dark)? d) Express λ in terms of w, D, and L? e) Solve for the numerical value of λ, in nanometers.