A leaky capacitor loses 22% of its charge in 13 min. What is the effective time constant of the system? The time constant, T = What fraction of charge (in %) will be on the capacitor after 39 min? Q Qo After what time there will be 4% of the initial charge left on the capacitor? The charge, The time, t = Units Select an answer x 100% = Units Select an answer Units Select an answer

A leaky capacitor loses 22% of its charge in 13 min. What is the effective time constant of the system? The time constant, T = What fraction of charge (in %) will be on the capacitor after 39 min? Q Qo After what time there will be 4% of the initial charge left on the capacitor? The charge, The time, t = Units Select an answer x 100% = Units Select an answer Units Select an answer

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The voltage across a capacitor is given by the formula V=Q/C, where Q is usually called "the charge on the capacitor." Where is this charge in a capacitor? Does the capacitor really have a net charge?
Two capacitors give an equivalent capacitance of 9.70 pF when connected in parallel and an equivalent capacitance of 2.00 pF when connected in series. What is the capacitance of each capacitor? smaller capacitor bigger capacitor pF pF
A 120 pF capacitor is charged to a potential difference of 45 V, and the charging battery is disconnected. The capacitor is then connected in parallel with a second (initially uncharged) capacitor. If the measured potential difference across the first capacitor drops to 34 V, what is the capacitance of this second capacitor? Number i Units
How much charge flows from each terminal of a 12.0- V battery when it is connected to a 6 20 jµF capacitor? Express your answer using three significant figures and include the appropriate units. HA Q = Talue Units
Q3 = In the shown Figure of network of capacitors, suppose C₁ C₂ C3 = 10 µF and the potential difference between points a and b (V) is 20 V. C₁ C₂ a) Determine the equivalent capacitance and the charge on the equivalent capacitor. a b) Determine both potential difference and charge for each capacitor.
A.) Determine Ceq for the combination of capacitors shown below. B.) Determine Ceq for the combination of capacitors shown below. Ceq C3= 10 F Ceq = C₁ = 16 F HE C₂ = 12 F HE C₁ = 2 F C3=9 F HE HI C3 = 17 F HE C4 = 5 F HH C4 = 2 F C.) Determine Ceq for the combination of capacitors shown below. D.) Determine Ceq for the combination of capacitors shown below. Ceq = Ceg C₂ = 8 F 18! = C₂ = 10 F HH C3= 15 F THI C4 = 13 F HH C₁ = 11 F C₁ = 18 F HE C4 = 18 F HH C₂ = 6 F
A combination of series and parallel connections of capacitors is shown in the figure. The sizes of these capacitors are given by the follow data:C1 = 5.3 μFC2 = 3.5 μFC3 = 8.5 μFC4 = 1.2 μFC5 = 0.95 μFC6 = 13.5 μF Find the total capacitance of the combination of capacitors in microfarads.
Three capacitors 2 µF, 6 µF, and 24 µF are connected in parallel to a battery of 240 V. Calculate the capacitance of the combination and the charge on each capacitor. (see figure 1)
Two capacitors give an equivalent capacitance of 10.76 pF when connected in parallel and an equivalent capacitance of 1.78 pF when connected in series. What is the capacitance in pF of the capacitor with the larger capacitance? Round your answer to 2 decimal places.
no handwritten answer needed
Two capacitors, 1 C and 2 C , give an equivalent capacitance of p C when connected in parallel and an equivalent capacitance of s C when connected in series. What is the capacitance of each capacitor?
A leaky capacitor loses 5% of its charge in 5 min. What is the effective time constant of the system? The time constant, τ = Units . What fraction of charge (in %) will be on the capacitor after 10 min? The charge, QQ0×100%QQ0×100% = Units . After what time there will be 4% of the initial charge left on the capacitor? The time, t = Units .