Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- In a pressurized pipe, water flows at 170 C. The standard atmospheric pressure is 101.312 kPa (abs) and the local atmospheric pressure is 97.727 kPa (abs). Determine the gage pressure and its equivalent water height value that allows the cavitation to start. Show all these values schematically.arrow_forwardAs shown in the figure below, a cylindrical tank with a hole in the bottom and an air vent in the top is being filled with water. Given the following: Dtank = 4 ft hill = 8 ft NOG height of water in tank when tank is filled Qin = 10 gal/min %3D NOT UPL TO CHE diameter of hole Find: volumetric flowrate into tank EGG EXAM into the tank in slugs/second OT UPS XAM O NOT U EXAM (c) The rate at which the water level in the tank is mass flowrate (in slugs/second) of the water (b) The mass flowrate (in slugs/second) out of the tank UPLOAD TO CHE NOT UPLOAD when the water level reaches the fill height DO NOT UPL rising (in inches/minute) when the water level NOT UPL PLOAD TO CHEGG NOT UPLOAD TO CHEGG EXAM TO CHEGG EXAM OD TO CHEGG UP reaches the filled height то снE LOAD vent Dtank DO DO DO NOT UPLOADTO EXAM EX DO 0 DONOT UPLOA T Dhole G EXAM TO CNGO UPLOA hole mdotoutarrow_forwardHow do I answer this question?arrow_forward
- A 100 kW pump is moving water at 1 m^3/min. If the inlet pressure is 200 kPa (gauge), what is the outlet pressurearrow_forwardIf a hole is drilled at the bottom of a full bucket of water of height. H 60 meter what is the second velocity and first if we have pressure 1 in the air is 103 kpa and pressure 2 760pa (proof the equation you used to solve it ) Kindly re-draw the diagram.arrow_forwardHaving trouble with this problem. Please include your assumptions, explanation, and any sketches. Any help would be appreciated!arrow_forward
- Gentlemen, please check and help me with question #3 Tank filled with water and orifice diameter of 3 cm in the bottom. Height between centre of orifice and water level 3 m. Coefficient of discharge - 0.64, coefficient of velocity- 0.97. Find: 1. Actual jet velocity? This one I know how to do. V(actual) = square root from 2gH 2. Jet diameter? This one I know as well. Coefficient of contraction= coefficient of discharge/ coefficient of velocity Diam of jet we will find from formula: Coefficient of contraction = (diameter of jet/diameter of orifice)^2 3. How long will it take for jet to be established?arrow_forwardA pipe delivers grape juice to a 1.5 m diameter tank. Another pipe (5 cm in diameter), located near the base of the tank is used to extract the grape juice from the tank. Calculate the rate of flow of juice into the tank if the surface of the juice remains constant at a height of 2.5 m. (Assuming the physical properties of grape juice as water and the acceleration due to gravity is 9.81 m / s2) = ... liters / minutearrow_forward
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