A large 3-phase, 4000 V, 60 Hz, squirrel- induction motor draws a current of 23 cage 385 A and a total active power of 2344 kW when operating at full-load. The correspon- ding speed is accurately measured and is found to be 709.2 r/min. The stator is con- nected in wye and the resistance between two stator terminals is 0.10 2. The total iron losses are 23.4 kW and the windage and friction losses are 12 kW. Calculate the following: a. The power factor at full-load b. The active power supplied to the rotor c. The total I'R losses in the rotor d. The load mechanical power [kW], torque [kN-m], and efficiency [%] 24 If we slightl.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.61P
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Number 23 

2)
a 11 at r/min. Wha
along a force
tive resis
Calculate the currer
as con-
ge in-
the ro-
Draw the complete coil connection
If the conducting l;
o braking force exer
A 3-phase, 5000 h
he same
27
-IXO..ddu
22
The 3-phase, 4-pole stator of Fig. 25 ho.
ency:
internal diameter of 250 mm and o
stacking
(OL 12
at 594 r/min. Wha
28
12-pole, wound-re
following:
a. The peripheral speed [m/s] of the
tor PR losses at r.
s of full-
d no-load
29m The motor in Pro
ob characteristics:
1. dc resistance
= 0.112 2 a
ase,
connected to a 60 Hz source
b. The peak voltage induced in the rotor bors
c. The pole-pitch
A large 3-phase, 4000 V, 60 Hz, squirrel-
cage induction motor draws a current of
385 A and a total active power of 2344 kW
when operating at full-load. The correspon-
ding speed is accurately measured and is
found to be 709.2 r/min. The stator is con-
peed and
percent.
2. dc resistanc
23
3. open-circui
slip-rings w
4. line-to-line
motor
cent and
late the
bub5. no-load sta
ppears
cor in-
6. active pow
load = 91
nected in wye and the resistance between
two stator terminals is 0.10Q. The total
iron losses are 23.4 kW and the windage
and friction losses are 12 kW. Calculate the
following:
a. The power factor at full-load
b. The active power supplied to the rotor
c. The total IR losses in the rotor
d. The load mechanical power [kW],
torque [kN-m], and efficiency [%]
ked.
d by a
7. windage a
8. iron losse
9. locked-rot
10. active po"
= 2207 k
by a
he
across
on as
Calculate edo
n as
a. Rotor and
75°C (ass
b. Voltage ar
ating
24
have (increase or decrease) upon
a. Starting torque
rotor whe
594 r/min
c. Reactive
nstan-
an an-
g current
to create
d. PR losse
speed
ictor
runs at m
onea
75°C)
e. Active Ț
output
he principle of magnetic levitation.
no-load
30
Transcribed Image Text:2) a 11 at r/min. Wha along a force tive resis Calculate the currer as con- ge in- the ro- Draw the complete coil connection If the conducting l; o braking force exer A 3-phase, 5000 h he same 27 -IXO..ddu 22 The 3-phase, 4-pole stator of Fig. 25 ho. ency: internal diameter of 250 mm and o stacking (OL 12 at 594 r/min. Wha 28 12-pole, wound-re following: a. The peripheral speed [m/s] of the tor PR losses at r. s of full- d no-load 29m The motor in Pro ob characteristics: 1. dc resistance = 0.112 2 a ase, connected to a 60 Hz source b. The peak voltage induced in the rotor bors c. The pole-pitch A large 3-phase, 4000 V, 60 Hz, squirrel- cage induction motor draws a current of 385 A and a total active power of 2344 kW when operating at full-load. The correspon- ding speed is accurately measured and is found to be 709.2 r/min. The stator is con- peed and percent. 2. dc resistanc 23 3. open-circui slip-rings w 4. line-to-line motor cent and late the bub5. no-load sta ppears cor in- 6. active pow load = 91 nected in wye and the resistance between two stator terminals is 0.10Q. The total iron losses are 23.4 kW and the windage and friction losses are 12 kW. Calculate the following: a. The power factor at full-load b. The active power supplied to the rotor c. The total IR losses in the rotor d. The load mechanical power [kW], torque [kN-m], and efficiency [%] ked. d by a 7. windage a 8. iron losse 9. locked-rot 10. active po" = 2207 k by a he across on as Calculate edo n as a. Rotor and 75°C (ass b. Voltage ar ating 24 have (increase or decrease) upon a. Starting torque rotor whe 594 r/min c. Reactive nstan- an an- g current to create d. PR losse speed ictor runs at m onea 75°C) e. Active Ț output he principle of magnetic levitation. no-load 30
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