(a) In the manufacture of paint, a specific solid additive is used to improve the property. The heat of fusion of the solid is 140 cal/g at a temperature of 10°C and pressure of 1 atm. The ratio of specific volume (m/kg) of solid and liquid is 1.120. Calculate the effect of saturated pressure on temperature (K/Pa).

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Thermodynamics

 

(a) In the manufacture of paint, a specific solid additive is used to improve the property. The
heat of fusion of the solid is 140 cal/g at a temperature of 10°C and pressure of 1 atm.
The ratio of specific volume (m³/kg) of solid and liquid is 1.120. Calculate the effect of
saturated pressure on temperature (K/Pa).
(b) A mixture of propane (1) and butane (2) is used as a fuel and the volume of the mixture
is given by:v (m³) = 0.0125 – 0.132 x1x2 – 0.0036 xỉ, where x, is the mole fraction of
component i. Calculate:
(i) the volume of propane when its mole fraction is 0.60.
(ii) the pure component volume of propane.
Given data:
R= 8.314 J/mol.K
dPsat
AHab = TAVab
dT
1 cal = 4.184 J
where a and b are the phases
°C +273 = K
| d(x") = n(x"-1)
1000 J= 1kJ
dM
1 bar = 105 N/m2
М — М+ х
dx1
dM
M2 = M – X1 dx,
g =
9.81 m/s?
Transcribed Image Text:(a) In the manufacture of paint, a specific solid additive is used to improve the property. The heat of fusion of the solid is 140 cal/g at a temperature of 10°C and pressure of 1 atm. The ratio of specific volume (m³/kg) of solid and liquid is 1.120. Calculate the effect of saturated pressure on temperature (K/Pa). (b) A mixture of propane (1) and butane (2) is used as a fuel and the volume of the mixture is given by:v (m³) = 0.0125 – 0.132 x1x2 – 0.0036 xỉ, where x, is the mole fraction of component i. Calculate: (i) the volume of propane when its mole fraction is 0.60. (ii) the pure component volume of propane. Given data: R= 8.314 J/mol.K dPsat AHab = TAVab dT 1 cal = 4.184 J where a and b are the phases °C +273 = K | d(x") = n(x"-1) 1000 J= 1kJ dM 1 bar = 105 N/m2 М — М+ х dx1 dM M2 = M – X1 dx, g = 9.81 m/s?
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