A hypothetical study concerned with estimating th187e amount of marijuana use per year among a teenage population obtained a sample of ll0 high-school students. With the following sample statistics, construct a 95-confidence interval around the mean number of times this sample uses marijuana in a given 6-month period: Mean of the sample = 5.3; the standard deviation of the sample = 4.3 and the sample size = 110 What does the interval you constructed tell us about marijuana use in the population? Interpret these results.

Q: A random sample of 64 business students required an average of 100 minutes to complete a statistics…

A: Given that, Mean = 100 Standard deviation = 20 Sample size = 64 95% confidence level

Q: A random sample of 121 observations has a mean of 23, a median of 24, and a mode of 25. The…

A:

Q: The data were collected in the men's 100-meter run of 16 secondary school students, and the mean…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: Calculate a 95% upper confidence bound for the mean of a normally distributed population using the…

A: given data  x¯ = 39316n = 14σ= 3276normal distribution 95% upper confidence bound = ?

Q: You measure 29 turtles' weights, and find they have a mean weight of 44 ounces. Assume the…

A:

Q: We take a sample of 50 people and obtain a sample mean of 147 pounds with a standard deviation of 15…

A: We have given that  Sample size n = 50 Sample mean = 147 Standard deviation = 15 90%confidence…

Q: You surveyed business travelers to develop quality ratings for an airport. The maximum possible…

A: Given,sample size(n)=25sample mean(x¯)=6.34sample standard deviation(s)=2.16degrees of…

Q: study of 45 members of the Mall Walkers group showed that they could walk at an average rate of 3.3…

A:

Q: the standard deviation of the 16 observations was 0.95 inches (again, the sample mean was 17.2).…

A: Given :  Standard deviation of the 16 observations was 0.95 inches & the sample mean was 17.2.…

Q: Calculate a 90% confidence interval for the mean paired difference between  the two population means…

A: In testing of hypothesis, Level of Significance is the probability of rejecting a null hypothesis…

Q: A sample of n = 43 data values randomly selected from a normally distributed population has varlance…

A: Degrees of freedom = n-1=43-1=42 (by using the standard normal table)

Q: For a sample 1000 app users, the research team reports an average age of 39. If the population…

A: given data  n = 1000 x¯ = 39σ = 9.590% ci, upper bound of ci  = ?

Q: An experiment was designed to estimate the mean difference in weight gain for pigs fed ration A as…

A: Solution: A B d=A-B (d-d) (d-d)2 63 61 2 -3 9 57 52 5 0 0 64 54 10 5 25 51 45 6 1 1 45…

Q: 90% confidence

A: Given that  90% Confidence interval for mean = ( 75.3 to 80.9 ) Null hypothesis (Ho) : μ=70…

Q: sample standard deviation of $74.50. a. Develop a  95% confidence interval estimate of the mean…

A: The sample size, i.e., the sampled number of families, n=64.The sample average spent amount(in $)…

Q: The local Health Department conducted a study in 2009 of 900 adults asking each adult the number of…

A: Given Information: Sample size (n) = 900 Sample mean (x¯) = 7.946 Standard deviation = 6.567…

Q: It is desired to obtain a 95% confidence interval for the mean time µ= 120 minutes to take the…

A:

Q: A random sample of 11 fields of spring wheat has a mean yield of 20.2 bushels per acre and standard…

A: Sample size, n=11 Sample mean, x¯=20.2 Sample sd, s=5.19 CL=0.99

Q: You measure the blackbody temperature of the night sky three times and read: 7.3C, 9.1C, and 8.7C.…

A: Given : 1.   Temperature f night sky(in  degree celcies)    : 7.3, 9.1, and 8.7. 2.   Sample  mean =…

Q: In a survey, 1000 adults in a certain country were asked how many hours they worked in the previous…

A: Confidence interval used to obtain the range where the population true mean lies. It explain the…

Q: A game involves tossing two coins and receiving 74 cents they are both heads. What is a fair price…

A: From the provided information, A game involves tossing two coins. Total outcomes tossing two coins =…

Q: A random variance survey of 495 adults found that 59 had diabetes. which of the following is a 98%…

A:

Q: A sample of 50 students was taken from the local university. These students spent an average of R170…

A: Given information- Sample size (n) = 50 Mean x̅ = R170 Standard deviation (s) = R25.50 Significance…

Q: A survey of 40 individuals who passed the seven exams and obtained the rank of Fellow in the…

A:

Q: A survey conducted by the American Automobile Association (AAA) showed that a family of four spends…

A: Given that: Population mean, μ=215.60 n = 64 x¯=252.45 s = 74.50

Q: Construct a 90% Confidence Interval for the mean.

A: Let  be the population mean of water per day.Given that,Sample size Sample mean Sample standard…

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: If a 90% confidence interval for µ is [15, 25],  then X=?, e=?

A: Note: Hello! Thank You for the question. We are considering 'e' as margin of error. From the given…

Q: A random sample of 64 business students required an average of 50.7 minutes to complete a statistics…

A: Margin of Error E = z(alpha/2) * s / sqrt(n)Lower Bound = X - z(alpha/2) * s / sqrt(n)Upper Bound =…

Q: Recent data from a national survey indicated that the average woman goes to a salon once every five…

A: We have given that the average woman goes to a salon once every five weeks and spend on average…

Q: A random sample of 25 business students required an average of 50.7 minutes to complete a statistics…

A: Given that, Mean = 50.7 Standard deviation = 10.4 Sample size = 25

Q: We take a simple random sample of 16 adults and ask them how long they sleep on atypical night. The…

A: The objective of this question is to calculate the 88% confidence interval for the true mean time…

Q: researcher is interested in finding a 95% confidence interval for the mean number Minutes students…

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Q: One​ year, the mean age of an inmate on death row was 38.1years. A sociologist wondered whether the…

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Q: In a random sample of 41 criminals convicted of a certain​ crime, it was determined that the mean…

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Q: If a 90% confidence interval for the mean is (75.3 to 80.9), we would reject H0:  =70 in favor of…

A: Given, 90% confidence interval (75.3,80.9) i.e. The hypothesis to be tested is given as:

Q: Find the value of ta/2 and n = 25 for the 90% confidence interval for the mean if the population…

A:

Q: You measure the blackbody temperature of the night sky three times and read: 7.3C, 9.1C, and 8.7C.…

A: Use the given data to form the excel table:   x x-μ x-μ2   7.3 -1.06667 1.1379…

Q: Suppose we gather a random sample of 20 data points. Assume the population standard deviation is 11.…

A: Given,   Sample size = 20 Sample mean = 23 Population standard deviation = 11   Since the population…

Q: number

A: Given: Mean, x=3.5 Sample standard deviation, s=1.6 Sample size, n = 219 To compute the confidence…

Q: sample of seven laptop computers had a variance of 25.88 years when the lifespan of the computer was…

A:

Q: A quality control expert at a drink bottling factory took a random sample of 9 bottles from a…

A: The sample size: n=9 The sample mean: x¯=505 mL The sample standard deviation: s=6 mL Confidence…

Q: a sample 1000 website users, the research department reports an average age of 39. If the population…

A: GIVEN DATA,n=1000x¯=39σ=9.5CI=0.90α=1-0.90=0.10α/2=0.10/2=0.05we have to find out the upper bound…

Q: # 2 A sample of 64 airplanes gave a mean air time (time spent flying) of 49 hours. If the standard…

A: Given,population standard deviation(σ)=14.8sample mean(x¯)=49sample size(n)=64