A hydrochloric acid solution consists of 42.0% HCI (36.46 g/mol) by mass and has a density of 1.14 g/mL. What volume of this solution is required to react completely with 1.00 g Al (26.982 g/mol) according to the chemical equation below? 6 HClag) + 2 Al(s) → 2 AlCl3(aq) + 3 H2(g) Select one: O a. 8.47 mL O b. 3.56 mL O c. 1.49 mL O d. 1.94 mL

Q: What mass of precipitate (in g) is formed when 72.8 mL of 0.500 M FeCl₃ reacts with excess AgNO₃ in…

A: From the reaction it is clear that 1 mole FeCl3 reacts with 3 moles AgNO3 to give 3 moles AgCl.…

Q: 250.0 mg of copper(II) sulfate pentahydrate (CuSO4•5H2O, 249.69 g/mol) was dissolved in water to…

A: Since mass of CuSO4•5H2O used = 250 mg = 0.25 g              (since 1 g = 1000 mg) Hence moles of…

Q: Silver Nitrate reacts with Sodium Chloride according to the following reaction: AgNO3 (aq) + NaCl…

A: Recall the given reaction,                                          AgNO3 aq + NaCl aq → AgCl s +…

Q: 100.0 mL of an aqueous solution containing 0.250 M KOH(aq) is mixed with 100.0 mL of an aqueous…

A: First of all, we need to write down the balanced chemical.  The molar mass of Fe(OH)3 = 106.87g/mol

Q: What mass of precipitate (in g) is formed when 85.7 mL of 0.500 M FeCl₃ reacts with excess AgNO₃ in…

A: Given precipitation reaction; FeCl3 (aq) + 3 AgNO₃(aq) → 3 AgCl(s) + Fe(NO₃)₃(aq) Given volume of…

Q: Say we have 32.0 mL of HCl.  What Molarity would the HCl need to be to make 5.830 grams of H2S?…

A: Given moles of H2S=5.830g Volume is 32ml Using the formula of molarity, calculate the molarity

Q: A mass of 0.4113 g of an unknown acid, HA, is titrated with NaOH(aq). If the acid reacts with 28.10…

A: Acid and base reacts with each other forms water and salt. This reaction is called neutralization…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO₃)₂ reacts with 33.0 mL of…

A:

Q: What quantity in moles of precipitate will be formed when 77.1 mL of 0.150 M AgNO3 is reacted with…

A:

Q: you begin with 78.2 mL of 0.725 M KCl(aq) solution and mix it with 67 mL of 0.721 M Pb(NO3)2(aq) ,…

A: Given-> Volume of KCl= 78.2 ml Molarity of KCl = 0.725 M Volume of Pb(NO3)2(aq) = 67 ml Molarity…

Q: AgNO₃(aq) → 3 AgCl(s) + Fe(NO₃)₃(aq)

A: This can be solved by balancing the equation.required solution is given below

Q: If 19.5 g of NaOH is added to 0.800 L of 1.00 M Zn(NO₃)₂, how many grams of Zn(OH)₂ will be formed…

A: Given, Mass of NaOH = 19.5 g            Molarity of Zn(NO₃)₂ = 1.00 M            Volume of Zn(NO₃)₂…

Q: An experiment is designed to determine the mass percent of sulfate in an unknown soluble sulfate…

A: Balanced chemical equation: BaCl₂ (aq) + Na₂SO₄ (aq) → BaSO₄ (s) + 2 NaCl (aq) From the above…

Q: How many moles of precipitate will be formed

A: Molarity = number of moles/volume of solution (in L)  Number of moles = molarity × volume (in L)

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 23.0 mL of…

A: Number of moles of substance=Concentration of substance x Volume of substanceFor…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO3)2 reacts with 20.0 mL of…

A: Here we are required to find the mass of precipitate formed during the given reaction  1L=1000 ml.

Q: What is the Molarity of a hydrochloric acid solution if 25.50 mL are required to neutralize 0.375 g…

A: Below attached file showing the details answer.  All the best.

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 31.0 mL of…

A: ZnNO32+2 NaOH→ZnOH2 s+2 NaNO3 aqStength of ZnNO32=20.5x0.700 M1000=0.0143Stength of NaOH=310x0.700…

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Li₃PO₄ reacts with 44.0 mL of…

A: The balanced reaction given is, => Li₃PO₄(aq) + Cr(NO₃)₃(aq) → CrPO₄(s) + 3 LiNO₃(aq) Given :…

Q: How many grams of AgCl will be formed when 60.0 mL of 0.500 M AgNO₃ is completely reacted according…

A:

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO3)2 reacts with 40.0 mL of…

A:

Q: How many moles of precipitate will be formed when 154.5 mL of 0.350 M NaCl is reacted with excess…

A:

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Na PO reacts with 62.5 mL of 0.200…

A: Since, Molarity is the number of moles of solute dissolve in one litre of the solution. Thus,

Q: what mass precipitate (in g) is formed when 20.5 mL of0.800 M Co(NO3)2 reacts with 29.0 mL of 0.800…

A:

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO₃)₂ reacts with 22.5 mL of…

A: According law of mass action, the same amount of mass involved in the reaction is formed as a…

Q: Consider the formation of chlorine gas, from household bleach (sodium hypochlorite) and hydrochloric…

A: Volume of chlorine gas collected = 4.96 L ~ 4.99 L Answer: Option A. 4.99 L

Q: How many moles of precipitate will be formed when 112.0 mL of 0.350 M NaCl is reacted with excess…

A: Given reaction:  2 NaCl (aq) + Pb(NO₃)₂ (aq) → PbCl₂ (s) + 2 NaNO₃ (aq) volume of 0.350 M NaCl…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 34.5 mL of…

A: First calculate moles for both solutions. Then using mol to mol ratio, find out moles of precipitate…

Q: What quantity in moles of precipitate will be formed when 45.6 mL of 0.550 M AgNO3 is reacted with…

A:

Q: How many moles of precipitate will be formed when 100 mL of 2.00 M NaBr is reacted with 70.0 mL of…

A: The mole of precipitate will be formed has to be determined

Q: Na2CO3(aq)  +  2  HCl(aq)  →   2 NaCl(aq)  +  CO2(g)  +  H2O 0.176 g of sodium carbonate required…

A:

Q: How many moles of precipitate will be formed when 69.3 mL of 0.350 M AgNO₃ is reacted with excess…

A: Given the chemical reaction as follows,2 AgNO3(aq) + MgI2(aq) → 2 AgI(s) + Mg(NO3)2(aq)we are asked…

Q: What mass of precipitate (in g) is formed when 80.0 mL of 0.500 M AlCl₃ reacts with excess AgNO₃ in…

A:

Q: If 28.5 g of NaOH is added to 0.800 L of 1.00 M Zn(NO₃)₂, what mass in grams of Zn(OH)₂ will be…

A: Given data mass of NaOH = 28.5 g volume of Zn(NO3)2 = 0.800 L molarity of Zn(NO3)2 = 1.00 M Reaction…

Q: What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M NaI is reacted with…

A:

Q: Consider the formation of chlorine gas, from household bleach (sodium hypochlorite) and hydrochloric…

A: The given reaction is, NaClO (aq) + 2 HCl (aq) → Cl2(g) + H2O (l) + NaCl (aq) The given parameters…

Q: Determine the volume (liters) of 0.500 M NaOH solution required to neutralize 1.50 L of 0.750 M…

A: In neutralization reaction, an acid reacts with a base, they neutralize each other to form a metal…

Q: A 1.40 g sample of H2X reacts completely with 30.0 mL of 0.400 M NaOH according to reaction:…

A: To solve this problem we have to calculate the molar mass of H2X

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Na₃PO₄ reacts with 58.5 mL of…

A: The given data contains, Volume of Na3PO4 =45.5 mlMolarity =0.300 M Volume of CrCl3 =58.5 mlMolarity…

Q: Determine the number of grams of HCl that can react with 0.750 g of Al(OH)₃…

A: From the given reaction we can see that 1 mole of Al(OH)₃ need 3 moles of HCl to react completely…

Q: What mass of precipitate (in g) is formed when 80.0 mL of 0.50 M AlCl₃ reacts with excess AgNO₃ in…

A: The balanced reaction taking place is given as, => AlCl₃ (aq) + 3 AgNO₃ (aq) → 3 AgCl (s) +…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO₃)₂ reacts with 25.5 mL of…

A: The reaction equation is- Ni(NO₃)₂(aq) + 2 NaOH(aq) → Ni(OH)₂(s) + 2 NaNO₃(aq) Moles of Ni(NO3)2 can…

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Li₃PO₄ reacts with 50.5 mL of…

A: Interpretation: The mass of precipitate (in g) is to be determined when 45.5 mL of 0.300 M Li3PO4…

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.