a) How you will differentiate Elastic region from Plastic region and Strain Hardening from Necking?
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- a) How you will differentiate Elastic region from Plastic region and Strain Hardening from Necking?
- b) Write a short note on Strength, Malleability and Tensile Strain.
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- On the stress-strain diagram of a steel bar, show and explain the following: proportional limit, yield stress, ultimate stress, yield strain, and modulus of elasticity.DISCUSS THE STRESS-STRAIN RELATIONSHIP SHOWN BELOW: (WRITE IN ENGINEERING LETTERING) Actual Rupture Point Ultimate Strength Elastic Limit Yield Point Rupture Point Proportionality Limit STEEL: Stress, o – Strain, e RelationsipSketch the stress-strain curve and explain it in relation to the tensile test for steel bars.
- A high-yield-strength alloy steel bar with a rectangular cross section that has a width of 37.5 mm, a thickness of 6.25 mm, and a gauge length of 203 mm was tested in tension to rupture, according to ASTM E-8 method. The load and deformation data were as shown in Table Using a spreadsheet program, obtain the following:a. A plot of the stress–strain relationship. Label the axes and show units.b. A plot of the linear portion of the stress–strain relationship. Determine modulus of elasticity using the best-fit approach.c. Proportional limit.d. Yield stress.e. Ultimate strength.f. If the specimen is loaded to 155 kN only and then unloaded, what is the permanent deformation?g. In designing a typical structure made of this material, would you expect the stress applied in (f) safe? Why?Determine the value of modulus of elasticity having stress value equal to 50 MPa and strain equal to 0.04 IIn the tensile stress-strain curve below, label the following: elastic stage, plastic stage, necking stage, ultimate tensile strength, fracture point.please write details
- Bending Stress Problems.An alloy steel having a diameter of 0.45 in. extends 0.002 in. over a gage length of 2.2 in. due to a tensile load of 3900 lb. What is the modulus of elasticity of this alloy steel? A)29,010 ksi B)27,000 ksi C)30,000 ksi D)28,000 ksiSketch a sample stress-strain behavior of steel and identify different levels of strength.
- An ASTM A615 grade 60 number 10 rebar with a gauge length of 8 in. was subjected to tension to fracture according to ASTM E-8 method. The load and deformation data were as shown in Table .Using a spreadsheet program, obtain the following:a. A plot of the stress–strain relationship. Label the axes and show units.b. A plot of the linear portion of the stress–strain relationship. Determine modulus of elasticity using the best-fit approach.c. Proportional limit.Determine stress and longitudinal strain} 8) A tensile load of 3000 N is applied to a steel bar of cross-sectional area 500 mm?. If a tensile load was applied to an aluminum bar to achieve the same lateral (transvers) strain with the former (steel bar), what would be the load? Note: Original dimensions of the two bars are the same (Est = 2.1 x 105 MPa, Eat = 0.703 × 105 MPa, vg = 0.3, vat = 0.33) E = º , v = - Saterat Eaxial Fatuminum™ 3000 N A-500 mm² A=500 mm² Fatuminum=? 3000 N Steel Aluminum