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- Suppose you walk 18.0 m straight west and then 25.0 m straight north. How far are you from your starting point? What is your displacement vector? What is the direction of your displacement? Assume the +x -axis is horizontal to the right.A trapper walks a 5.0-lan straight-line distance from her cabin to the lake, as shown in the following figure. Determine the east and north components of her displacement vector. How many more kilometers would she have to walk if she walked along the component displacements? What is her displacement vector?An aircraft undergoes two displacements. If the first displacement is directed at an angle of 225 with the positive x axis and has magnitude 30.0 miles, and if the resultant displacement is directed at an angle of 75.0 with the positive x axis and magnitude 22.0 miles, what are the magnitude and direction of the second displacement?
- Assuming the +x-axis is horizontal to the right for the vectors in the preceding figure, find (a) the component of vector Aalong vector C , (b) the component of vector Calong vector A , (c) the component of vector i along vector F , and (d) the component of vector Falong vector i .The components of vector A are A = - 3.5 and A =- 5.4, and the components of vector ; are B = - 4.3 and B =7.2. What is the angle (less than 180 degrees) between vectors A and B ? O A. 26° ОВ. 125° ОС. 116° O D. 64° ОЕ. 163°1. You are trying to find your family's hidden treasure by your ancestor using a map. The map says that starting from your house, first, you need to walk 3.00m, East. After that, you again walk 3.00m, 60O N of E. Then go 2.00m North. And finally move 4.00m, 300 S of W. If the treasure's location is the resultant vector. Find the magnitude and direction of the treasure. (Use component method)
- A. A cuclist yo rides 4.0 km due east. then 12.0km 21° west O of northe From this ooint she rides 7o km due wes What is the final dis place ment from where the cyclist started Cin km 32 (Éxpress our onswer in vector formo Assume the axis is to the x-Qtis O is to the east iand the't t-Q tis northe 2eyVector A is 9 m, 60.0o North of East and Vector B is 3 m 30.0o West of North. What is the resultant vector A + B in bearing form?A. 309 m, 30.8o West of SouthB. 11.7 m, 52.6o North of EastC. 305 m, 61.4o North of EastD. 10.8 m, 73.9o North of EastVector A has a magnitude 5.00 and points in a direction 40.0 degrees clockwise from the negative y-axis. What are the x- and y-components of vector A. O a. Ax = 4.29 and Ay = 2.16 O b. Ax = 3.83 and Ay = 3.21 c. Ax = -3.21 and Ay = 3.83 O d. Ax = 3.83 and Ay = -3.21 O e. Ax = -3.21 and Ay = -3.83
- H.W O vector A is(2m) Long and is 60above the X axis. vector B is (am) Long and is.60 below the Xaxis ind the vector difference A-B and B-A the vector sumA+BThe maghitude of vector A is 8.6. Vector lies in the fourth quadrant and forms an angle of 37° with the x-axis. What are the components of vector A? 37° A = 8.6 O a. Ax = 8.6, Ay = -8.6 O b. Ax = -6.9, Ay = 5.2 O C. Ax = 6.9, Ay = -5.2 O d. Ax = -6.9, Ay = -5.2If the vector A=4i + 2dj and B=5i - j are perpendicular (oleio ). What is the value of the constant d? O A. 10 О В. 20 O C. 5 O D. None ОЕ. 15