A hospital claims that the proportion,  p , of full-term babies born in their hospital that weigh more than  7  pounds is  42% . In a random sample of  195  babies born in this hospital,  62  weighed over  7  pounds. Is there enough evidence to reject the hospital's claim at the  0.05  level of significance? Perform a two-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. The null hypothesis: H0:   The alternative hypothesis: H1:   The type of test statistic: (Choose one)ZtChi squareF             The value of the test statistic: (Round to at least three decimal places.)   The p-value: (Round to at least three decimal places.)   Can we reject the claim that the proportion of full-term babies born in their hospital that weigh more than  7  pounds is  42% ?   Yes     No

Round to two decimal places as needed.

The quality manager believes there may be a relationship between the experience level of an inspector and whether a product passes or fails inspection. Inspection records were reviewed for 630 units of a particular product, and the number of units that passed and failed inspection was determined based on three inspector experience levels. The results are shown in the following table. (Table is the picture) b. Calculate the value of the test statistic. (Round the intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) Test Statistic =   c. Find the p-value.  0.01 ≤ p-value < 0.025 p-value < 0.01 0.025 ≤ p-value < 0.05 p-value ≥ 0.10 0.05 ≤ p-value < 0.10

Netflix is considering a new romcom (romantic comedy) series. Before making a final decision, the producers design an experiment to estimate the proportion of viewers who would watch the series. A random sample of 680 viewers was selected and asked to watch the first two episodes. After viewing the episodes, 425 viewers indicated they would watch the new series. (Round your answers to 3 decimal places.) a. Find the value of the sample proportion of people who would watch the new series. Sample proportion 0.625 b. Find an interval for the unkonwn population proportion of people who would watch the new series if the probability of this equal distance (to center) interval is 99%. interval is between 0.583 X and 0.667 X