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A horizontal spring with a spring constant of 20.0 N/m is attached to a 0.750 kg
mass on a horizontal, frictionless table. The mass is pulled until the spring is
stretched to 10.0 cm, then released at time t = 0 s.

At what time will the mass first pass the equilibrium position?
At what position is the block after 1.00 second?

 How fast is it going when it passes the equilibrium position?

Expert Solution
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Introduction:

We are given extension in spring. This is the amplitude of oscillation. We find angular frequency and hence equation for Simple harmonic motion. We then find the time and position. We then find the speed at equilibrium position using conservation of energy.

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In the first part, I'm confused about why pi/2 is used when solving for t.

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In the first part, I'm confused about why pi/2 is used when solving for t.

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