A homogeneous square block of mass m = 1 kg and side length l = 6 m rests on a m %3D m horizontal surface. The bottom right corner pivot of the block is attached to the surface by a pivot. A point particle of the same mass m = 1 kg moving horizontally with speed v = 64 m/s, as shown in the figure, hits the block at its upper left corner and sticks to the corner where it hits. (Moment of inertia of a homogeneous square of mass m and side length l around its center of mass is I = ml²/6.) What is the moment of inertia of the particle, when it is at the upper left corner of the block it stuck, around the pivot? (a) 72 kg-m² (e) 48 kg- m? (b) 36 kg-m² (c) 96 kg-m² (d) 648 kg-m²

A homogeneous square block of mass m = 1 kg and side length l = 6 m rests on a m %3D m horizontal surface. The bottom right corner pivot of the block is attached to the surface by a pivot. A point particle of the same mass m = 1 kg moving horizontally with speed v = 64 m/s, as shown in the figure, hits the block at its upper left corner and sticks to the corner where it hits. (Moment of inertia of a homogeneous square of mass m and side length l around its center of mass is I = ml²/6.) What is the moment of inertia of the particle, when it is at the upper left corner of the block it stuck, around the pivot? (a) 72 kg-m² (e) 48 kg- m? (b) 36 kg-m² (c) 96 kg-m² (d) 648 kg-m²