A heavy, 2.0 kilogram ball hangs from a thin string. An identical thin string hangs from below the heavy ball. Which string will break first, top or bottom, if you give the bottom string a quick, sharp pull? Explain your reasoning.

Sneak E. Fox Scheme #2: Hoist an Acme brand anvil into the air and drop it onto the bird, using a rope over a steel shaft.  The anvil is made of steel and weighs 250 lbs. How much force on the free end of the rope does it take to hold the anvil in place? how much force on the rope is required to lift the anvil into place? is the fox able to hold the anvil using the rope?  Can the fox lift the anvil using the rope?

Two masses, m, = 2.16 kg and m, = 9.71 kg are on a horizontal frictionless surface and they are connected together with a rope as shown in the figure. The rope will snap if the tension in it exceeds 50.0 N. What is the maximum value of the force F which can be applied? Submit Answer Tries 0/10 What is the acceleration of the whole system, when this maximum force is applied? 4.212m/s 2 Submit Answer Incorrect. Tries 1/10 Previous Tries

Problem 4: A ball of mass m is connected to two rubber bands of length L, cach under temsion T, as shown in the Figure. Assume the tension does not change. (a) The ball of mass m is in equilibrium. Draw a free-body diagram on m. (b) Since the ball of mass m is in equilibrium, Enet y = 0. Use Fnet.y=0 to find the equilibrium position for the ball yo. Hint: sin 0=yo/L, Answer: yo = mgL/(2T'). |Yo L. T. L т (c) The ball of mass m is now displaced slightly from equilibrium, as shown in the figure below. Draw a free-body diagram on m. (d) Use Newton's 2nd Law: Fnet,y = ma = -m to show that the motion of m satisfies the SHM differential equation + w²u = 0, where u = y – Yo and w = since the downward gravitational force on the ball is larger than the two upward tension forces on the ball. Hint: sin 0 = y/L. Also, from part (b), yo = mgL/(2T). We can rewrite this expression as mg = 2T(yo/L). Use this expression to substitute for mg in Newton's 2nd Law: Fnet.y = -ma = -my | 2T. For this problem…