A grouped frequency distribution should be used instead of a frequency distribution when the O distribution is bimodal. 2 distribution is skewed. 3 variable is continuous.

for normal distribution mean is 50 liter per hour and standard deviation is 10 liter per hours . find the 68%,95%and 99.7% values by using emperical graph  explain graph with all values

Post your created histogram. How would you describe the distribution? (Symmetric, skew left, skew right? Is it unimodal or bimodal?) Picture is below .

How to use a power calculator to compute power for the t distribution?

Explain, whether the data can be calculated if the hypergeometric distribution is not known the number of populations?

The average American gets a haircut every 34 days. Is the average smaller for college students? The data below shows the results of a survey of 15 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 23, 32, 38, 31, 39, 35, 25, 30, 36, 40, 27, 23, 32, 25 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv Hi: ?vSelect an answerv c. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is 2v a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that.. O The data suggest the population mean is not significantly lower than 34 at a = 0.10, so there M 24 3. 4. 5 6. 7 EU

Use the Histogram tool to develop a frequency distribution and histogram for the number of months as a customer of the bank in the data below. Compute the relative and cumulative relative frequencies and use a line chart to construct an ogive.   Complete the frequency distribution for the months as a​ customer, and compute the relative and cumulative relative frequencies. ​(Type integers or decimals rounded to three decimal places as​ needed.) Bins Frequency Relative Frequency Cumulative Relative Frequency 10 enter your response here   enter your response here   enter your response here   20 enter your response here   enter your response here   enter your response here   30 enter your response here   enter your response here   enter your response here   40 enter your response here   enter your response here   enter your response here   50 enter your response here   enter your response here   enter your…

How to construct the frequency distributions? Write down the steps.

For the residents in 2014, use R to calculate the interval with 99% certainty that the interval contains the actual population mean of the residents by census tracts. Type in the interval with keyboard. We also know that in each year, the number of residents by census tract in the State of Maryland follows a normal distribution, and the variance in the number of residents within the State of Maryland is the same for different years.  POP2014: 3072, 1989, 3794, 2689, 3211, 3722, 4385, 4009, 7598, 3862, 3097, 2726, 4881, 4157, 2570, 2512, 2518, 4863, 4147, 7139, 6067, 6819, 3705, 3239, 3824, 4977, 2576, 2940, 9791, 5231, 5634, 5337, 4205, 3888, 5562, 3335, 3770, 1808, 2045, 1532, 5420, 4993, 6109, 4377, 5424, 4976, 4507, 3738, 2827, 3485, 1559, 5199, 4702, 3971, 3803, 3356, 4670, 3816, 5477, 4760, 3126, 3630, 3755, 3795, 2578, 3382, 4005, 2442, 6096, 3799, 3843, 3836, 6046, 6431, 3561, 3142, 4829, 5058, 2471, 6119, 3523, 3094, 3146, 3356, 2618, 2366, 4266, 4016, 6080, 1554, 6878, 3645,…

The chart to the right shows that a professor's grading distribution is bell shaped, or normally shaped. The mean of the distribution is 74 and the standard deviation is 9. Using a Continuous Variable Normal Bell Distribution Model, calculate the minimum test score needed to score in the top 5% of the class. Complete your work in the worksheet by listing the formula inputs, labels for the formula inputs and make your calculations with formulas. This test problem is similar to what you studied in video # 32, 33 and 34 and homework problems # 17, 21 and 23. Relative Frequency Frequency Professor looks at all test score for a particular test (this is population data), and observes: 0.5 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 0.05 0 Mean = 74 Median = 74 Mode = 73 SD=9 0 0 0 up to 10 up 10 to 20 0 20 up to 30 0 30 up to 40 2 40 up to 50 29 50 up to 60 X = Score 112 60 up to 70 225 70 up to 80 111 80 up to 90 21 2 90 up 100 up to 100 to 110