A global positioning system (GPS) satellite moves in a circular orbit with period 11 h 58 min. (Assume the mass of the earth is 5.98 x 1024 kg, and the radius of the earth is 6.37 x 106 m.) (a) Determine the radius of its orbit (in m). m (b) Determine its speed (in m/s). m/s (c) The nonmilitary GPS signal is broadcast at a frequency of 1 575.42 MHz in the reference frame of the satellite. When it is received on the Earth's surface by a GPS receiver, what is the fractional change in this frequency due to time dilation as described by special relativity? = (d) The gravitational "blueshift" of the frequency according to general relativity is a separate effect. It is called a blueshift to indicate a change to a higher frequency. The magnitude of that fractional change is given by Af AU f mc² = where U, is the change in gravitational potential energy of an object-Earth system when the object of mass m is moved between the two points where the signal is observed. Calculate this fractional change in frequency due to the change in position of the satellite from the Earth's surface to its orbital position.

The ocean is not flat, because the Earth is curved. Take the radius of the Earth to be 6.38 × 103 km. How many meters lower will its surface be 32.0 km from the ship as measured along a line that is tangent to the surface of the Earth at the location of the ship?

Part (a)  Do this for the range r > R.  E = _____ Part (b)  Do this for the range r < R.  E = _____

I need help with a math question: Given that x = position, v = velocity, a = acceleration, m = mass. Which of the following will have units of kg * m/s^2 and why? m ∫ a dt m ∫ v dt 1/2m dv^2/dx m ∫ x dt 1/2m dv^2/dt  m dx/dt m dv/dt m da/dt 1/2m ∫ v^2 dt I am including an image/reference table. Thanks!