A given population proportion is.25. For the given value of n, what is the probability of getting each of the following sample proportions? (Round all z values to 2 decimal places, e.g. 0.75. Round all intermediate calculations and answers to 4 decimal places, e.g. 0.7275.) a. n = 110 and p≤.21 p= b. n = 33 and > .24 p= c. n = 59 and .24 ≤p<.27 p= d. n=80 and > .30 p= e. n = 800 and p > .30 p=
A given population proportion is.25. For the given value of n, what is the probability of getting each of the following sample proportions? (Round all z values to 2 decimal places, e.g. 0.75. Round all intermediate calculations and answers to 4 decimal places, e.g. 0.7275.) a. n = 110 and p≤.21 p= b. n = 33 and > .24 p= c. n = 59 and .24 ≤p<.27 p= d. n=80 and > .30 p= e. n = 800 and p > .30 p=
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 26PFA
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![A given population proportion is.25. For the given value of n, what is the probability of getting each of the following sample proportions?
(Round all z values to 2 decimal places, e.g. 0.75. Round all intermediate calculations and answers to 4 decimal places, e.g. 0.7275.)
a. n = 110 and p < .21
p=
b. n = 33 and > .24
p=
c.n=59 and .24 < p < .27
p=
d. n = 80 and > .30
p=
e. n = 800 and p > .30
p=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0842b344-c7d5-4c3e-ba44-bf4c8906a0a3%2F1c2f8b0a-8aa8-4700-b24f-b2019fac4cf8%2Fohoabe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A given population proportion is.25. For the given value of n, what is the probability of getting each of the following sample proportions?
(Round all z values to 2 decimal places, e.g. 0.75. Round all intermediate calculations and answers to 4 decimal places, e.g. 0.7275.)
a. n = 110 and p < .21
p=
b. n = 33 and > .24
p=
c.n=59 and .24 < p < .27
p=
d. n = 80 and > .30
p=
e. n = 800 and p > .30
p=
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