A girl of mass m₁ = 60.0 kilograms springs from a trampoline with an initial upward velocity of v; = 8.00 meters per second. At height h = 2.00 meters above the trampoline, the girl grabs a box of mass m2 = 15.0 kilograms. (Figure 1) For this problem, use g = 9.80 meters per second per second for the magnitude of the acceleration due to gravity. Figure m2 Iu h 1 of 1 Part D What is the maximum height max that the girl (with box) reaches? Measure max with respect to the top of the trampoline. Express your answer numerically in meters. View Available Hint(s) Hint 1. How to approach the problem Use conservation of energy. From Part B you know the velocity of the girl/box system just after the girl grabs the box. Therefore, you can compute the kinetic energy Kafter of the girl/box system just after the collision. You can also compute the gravitational potential energy Uafter of the girl/box system at this point. The sum of these two quantities must equal the gravitational potential energy of the girl/box system at the height hmax (where their velocity, and therefore kinetic energy, will be zero). Hint 2. Finding Uafter What is the girl/box system's gravitational potential energy Uafter immediately after she grabs the box? Express your answer numerically in joules. ΑΣΦ Uafter = Submit Request Answer ? J Hint 3. Finding Kafter What is the girl/box system's kinetic energy Kafter immediately after she grabs the box? Express your answer numerically in joules. Kafter = ΜΕ ΑΣΦ Submit Request Answer hmax = | – 4.09 ΑΣΦ Submit Previous Answers Request Answer × Incorrect; Try Again ? m ? J

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A girl of mass m₁ = 60.0 kilograms springs from a trampoline with an initial upward velocity of v; = 8.00 meters per second. At
height h = 2.00 meters above the trampoline, the girl grabs a box of mass m2 = 15.0 kilograms. (Figure 1)
For this problem, use g = 9.80 meters per second per second for the magnitude of the acceleration due to gravity.
Figure
m2
Iu
h
1 of 1
Transcribed Image Text:A girl of mass m₁ = 60.0 kilograms springs from a trampoline with an initial upward velocity of v; = 8.00 meters per second. At height h = 2.00 meters above the trampoline, the girl grabs a box of mass m2 = 15.0 kilograms. (Figure 1) For this problem, use g = 9.80 meters per second per second for the magnitude of the acceleration due to gravity. Figure m2 Iu h 1 of 1
Part D
What is the maximum height max that the girl (with box) reaches? Measure max with respect to the top of the trampoline.
Express your answer numerically in meters.
View Available Hint(s)
Hint 1. How to approach the problem
Use conservation of energy. From Part B you know the velocity of the girl/box system just after the girl grabs the
box. Therefore, you can compute the kinetic energy Kafter of the girl/box system just after the collision. You can
also compute the gravitational potential energy Uafter of the girl/box system at this point. The sum of these two
quantities must equal the gravitational potential energy of the girl/box system at the height hmax (where their
velocity, and therefore kinetic energy, will be zero).
Hint 2. Finding Uafter
What is the girl/box system's gravitational potential energy Uafter immediately after she grabs the box?
Express your answer numerically in joules.
ΑΣΦ
Uafter =
Submit
Request Answer
?
J
Hint 3. Finding Kafter
What is the girl/box system's kinetic energy Kafter immediately after she grabs the box?
Express your answer numerically in joules.
Kafter =
ΜΕ ΑΣΦ
Submit
Request Answer
hmax = | – 4.09
ΑΣΦ
Submit Previous Answers Request Answer
× Incorrect; Try Again
?
m
?
J
Transcribed Image Text:Part D What is the maximum height max that the girl (with box) reaches? Measure max with respect to the top of the trampoline. Express your answer numerically in meters. View Available Hint(s) Hint 1. How to approach the problem Use conservation of energy. From Part B you know the velocity of the girl/box system just after the girl grabs the box. Therefore, you can compute the kinetic energy Kafter of the girl/box system just after the collision. You can also compute the gravitational potential energy Uafter of the girl/box system at this point. The sum of these two quantities must equal the gravitational potential energy of the girl/box system at the height hmax (where their velocity, and therefore kinetic energy, will be zero). Hint 2. Finding Uafter What is the girl/box system's gravitational potential energy Uafter immediately after she grabs the box? Express your answer numerically in joules. ΑΣΦ Uafter = Submit Request Answer ? J Hint 3. Finding Kafter What is the girl/box system's kinetic energy Kafter immediately after she grabs the box? Express your answer numerically in joules. Kafter = ΜΕ ΑΣΦ Submit Request Answer hmax = | – 4.09 ΑΣΦ Submit Previous Answers Request Answer × Incorrect; Try Again ? m ? J
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