A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 178 yellow peas. Use a 0.05 significance level to test the claim that under the same​ circumstances, 27​% of offspring peas will be yellow. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution.   a. What is the test​ statistic? z equals ​(Round to two decimal places as​ needed.)   b. What is the​ P-value? ​P-value equals ​(Round to four decimal places as​ needed.)

If the variance in the weights of one sample of 12 oz. cookies is 3 oz. and the variance in a second sample, made in another factory, is only 1 oz. is there a real difference in variances between the two? (Estimate at 95% probability level, using 2-tail test). Use the appropriate test statistic to determine this, and assume there are 9 degrees of freedom for each sample. Yes no maybe none of the above.

Conduct a two-sample t-test at a 1% level of significance to find out if the mean U.S. stock return significantly outperforms the mean US bond return using the monthly data covering the sample period 1980-2020. Draw your conclusion by both the P value method and the Critical Value Method. Use t-test: Two sample Assuming unequal variances in Excel to obtain the Excel printout. data attached - confirmed data is correct

Two different types of catalysts are used in a chemical process. We want to conduct a hypothesis test to see if there is a difference in the yields at 5% significance level. Assume both populations are normaly distributed. To this end, we collect a simple random sample from each process. Assume equal variances. = = n-11, n=13,x,-90, x 91.4, 8, 4, 8=4.5

A poll of 1182 Americans showed that 47.2% of the respondents prefer to watch the news rather than read or listen to it. Use those results with a 0.01 significance level to test the claim that fewer than half of Americans prefer to watch the news rather than read or listen to it. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Begin by using the original claim to create a null hypothesis and an alternative hypothesis. The null hypothesis (denoted by Ho) is a statement that the value of a population parameter (such as proportion, mean, or standard deviation) is equal to some claimed value. The alternative hypothesis (denoted by H, or H, or HA) is a statement that the parameter has a value that somehow differs from the null hypothesis.

An independent-measures research project has two sample variances, 12 and 6. Calculate the F-Max test for this project. Your answer will be a whole number

Suppose that 90% of Narnians are children, that Narnian children have normallydistributed BMIs with a mean of 25 kg/m2and variance of 64 (kg/m2) 2, and that Narnianadults have normally distributed BMIs with a mean of 30 kg/m2and variance of 100(kg/m2)2. WHO currently categorizes BMIs greater than 30 as obese.a. What is the prevalence of obesity among Narnian children?b. What is the prevalence of obesity among Narnian adults?c. What is the overall prevalence of obesity among Narnians?d. Are age and obesity statistically independent in Narnia?e. What proportion of Narnians are obese children?f. What proportion of obese Narnians are children?

A researcher decides to measure anxiety in group of bullies and a group of bystanders using a 23-item, 3 point anxiety scale.  Assume scores on the anxiety scales are normally distributed and the variance among the group of bullies and bystanders are the same. A group of 30 bullies scores an average of 21.5 with a sample standard deviation of 10 on the anxiety scale.  A group of 27 bystanders scored an average of 25.8 with a sample standard deviation of 8 on the anxiety scale. You do not have any presupposed assumptions whether bullies or bystanders will be more anxious so you formulate the null and alternative hypothesis based on that.