A genetic experiment involving peas yielded one sample of offspring consisting of 445 green peas and 164 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 23% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p= 0.23 О В. Но: р30.23 H:p>0.23 H,:p<0.23 Ос. Но: р#0.23 O D. Ho: p= 0.23 H4:p=0.23 H,: p#0.23 ОЕ. Но: р#0.23з O F. Ho: p#0.23 H: p<0.23 H4:p>0.23 What is the test statistic? z= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.)

A:

A: Solution: The percentage of body fat measured at the beginning of the semester and at the end of the…

A:

A:

A:

A:

A: here differentiate both sides with respect to x.

A: Introduction: Suppose X and Y follow the bivariate normal distribution with mean and variance of X…

A: To simplify the expression means writing it in the simplest form.

A: We have to solve for x

A: Given differential equation is: x2d2ydx2+xdydx+y=-7.     …..1 Substitute x=ez z=logx Now,…

A:

A: Use the substitution method, to simplify the integral ∫x+172x112dx.…

A:

A:

A: Image is attached with detailed solution.

A: