7. A genetic experiment involving peas yielded one sample of offspring consisting of 445 green peas and 164 yellow peas. Use a 0.01 significance level to test the claim that underthe same circumstances, 23% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, andfinal conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.What are the null and alternative hypotheses?О А. Но: р-0.23О В. Но: р-0.23H1:p<0.23H1:p>0.23Ос. Но: р#0.23H1: p= 0.23O D. Ho: p=0.23H4:p#0.23O E. Ho: p+0.23O F. Ho: p#0.23H1:p<0.23H1:p>0.23What is the test statistic?(Round to two decimal places as needed.)What is the P-value?P-value =(Round to four decimal places as needed.) What is the conclusion about the null hypothesis?A. Reject the null hypothesis because the P-value is greater than the significance level, a.B. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.C. Fail to reject the null hypothesis because the P-value is greater than the significance level, .D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, .What is the final conclusion?A. There is not sufficient evidence to support the claim that less than 23% of offspring peas will be yellow.B. There is sufficient evidence to support the claim that less than 23% of offspring peas will be yellow.C. There is sufficient evidence to warrant rejection of the claim that 23% of offspring peas will be yellow.D. There is not sufficient evidence to warrant rejection of the claim that 23% of offspring peas will be yellow.

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A genetic experiment involving peas yielded one sample of offspring consisting of 445 green peas and 164 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 23% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p= 0.23 О В. Но: р30.23 H:p>0.23 H,:p<0.23 Ос. Но: р#0.23 O D. Ho: p= 0.23 H4:p=0.23 H,: p#0.23 ОЕ. Но: р#0.23з O F. Ho: p#0.23 H: p<0.23 H4:p>0.23 What is the test statistic? z= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.)