A genetic experiment involving peas yielded one sample of offspring consisting of 429 green peas and 154 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p#0.26 ОВ. Но: рж0.26 H:p>0.26 H:p<0.26 OC. Họ: p=0.26 O D. Ho: p#0.26 H:p#0.26 H:p<0.26 OF. Ho: p#0.26 O E. Ho: p=0.26 H: p>0.26 H1:p=0.26 What is the test statistic? (Round to two decimal places as needed.) What is the P.value? P-value =O (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. O B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. OC. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. O D. Reject the null hypothesis because the P-value is greater than the significance level, a.

In mathematics, everyone must have heard the term average in one place or other. Almost all types of calculation require taking out an average. In everyday life, the term is used for denoting a certain amount that can be said to be a typical quantity for…