Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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A gas is formed in the reaction shown below. The
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- [Tutorial: Limiting reactant stoichiometry] This question will walk you through the steps of calculating the mass of products produced based on your determination of the limiting reactant. b) Step 2a: Use dimensional analysis to determine the theoretical yield of the product. Calculate the theoretical yield in grams Al₂O₃ from the complete reaction of 64.7 grams Al according to the following balanced chemical equation: 2 Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2 Fe(s) c) Calculate the theoretical yield in grams Al₂O₃ from the complete reaction of 201 grams Fe₂O₃ according to the following balanced chemical equation: 2 Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2 Fe(s) d) Which of the following substances is the limiting reactant? e) What is the mass in grams of the excess Fe₂O₃ remaining after the partial reaction of 201 g Fe₂O₃ with 64.7 g Al? Give your answer to three significant figures.arrow_forwardIs H₂O₂ being created or destroyed by the chemical reaction? If H₂O2 is being created or destroyed, what is the rate at which it is being created or destroyed 1000 seconds after the reaction starts? Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol. If H₂O₂ is being created or destroyed, what is the average rate at which it is being created or destroyed during the first 1000 seconds of the reaction? Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol. ооо created destroyed neither created nor destroyed 0 x10 00 X Ś 0arrow_forwardIf you have 35.67g of Copper (II) Sulfate how many grams of just copper are present? Convert 35.67g of Copper (II) Sulfate into mols . Convert 35.67g of Copper (II) Sulfate into molecules of Copper (II) Sulfate.arrow_forward
- The human body burns glucose (C6H₁2O6) for energy according to this chemical reaction: C6H12O6 +60₂-6CO₂ + 6H₂O The products of the reaction are carbon dioxide (CO₂) and water (H₂O). Interestingly, all of the carbon dioxide and much of the water exits the body through the lungs: on every breath, the average person exhales 500. mL of air, which is typically enriched to 4% CO₂ and 5% water vapor by volume. In short, when a person loses weight by dieting, the weight that is lost actually departs his body as a gas, every time he exhales. Each kilogram of body fat lost requires exhaling about 2.9 kg of carbon dioxide. Calculate how many breaths it takes an average person to "exhale" 1.00 kg of fat. Round your answer to the nearest thousand. You'll need to know that the density of CO₂ is 2.0 kg/m³. 0 ☐ ☐x10 Xarrow_forwardConsider the following chemical reactions: KClO3 (s) ----------> KCl(s) + O2(g) NaNO3(s) ---------> NaNO2(s) + O2(g) 5.0000 g mixture of potassium chlorate and sodium nitrate is decomposed and the mass of residuals is 3.8600 g. The oxygen gas is collected in 359. mL. container at 25 oC by water displacement technique. Calculate the total pressure in mmHg. the vapor pressure of H2O at 25oC is 18.3 mmHg. K = 39.10 g/mole, Cl = 35.45 g/mole, Na = 22.99 g/mole, N = 14.00 g/mole and O = 16.00 g/molearrow_forwardWhat volume of NH3 is produced in the following reaction when 3.0 L N₂ reacts with 4.0 L of H₂? N₂(g) + 3H₂(g) →→→ 2NH3(g) Files Accepted file types All file types H 4 You can drag and drop files here to add them. a ⠀⠀⠀arrow_forward
- Consider the following balanced equation. 3 Ag(s) + 4 HNO3(aq) → 3 AgNO3(aq) + NO(g) + 2 H2O(l) A student used 117.24 g of Ag and obtained 135.49 g of AgNO3, calculate the percent yield of AgNO3. Give your answer to the correct number of significant figures without unit. Molar mass of Ag: 107.87 g/mol Molar mass of HNO3: 63.01 g/mol Molar mass of AgNO3: 169.87 g/mol Molar mass of NO: 30.01 g/mol Molar mass of H2O: 18.02 g/molarrow_forwardIf you wanted to produce 4 moles of SO3 gas, how many moles of SO2 would you need to react? (Assume an unlimited supply of O2 gas.) 2 SO₂ (g) + O₂(g) →2 SO, (g)arrow_forwardA student prepares phosphorous acid by reacting solid phosphorous triiodide with waterPI₃(s) + 3 H₂O(l) → H₃PO₃(s) + 3 HI(g)The student needs to obtain 0.359 L of phosphorous acid (d=1.651g/mL). The procedure calls for a 43.3 % excess of water and a yield of 70.8%. How much phosphorous triiodide should be weighed out?arrow_forward
- Ammonium nitrate has been used as a high explosive because it is unstable and decomposes into several gaseous substances. The rapid expansion of the gaseous substances produces the explosive force. NH,NO3 (8) → N2 (g)+ O2 (g) + H2O(g) Calculate the mass of each product gas if 47.4 g of ammonium nitrate reacts. g N2 g O2 g H2Oarrow_forwardA 6.79 g sample of NH, gas and a 6.79 g sample of HCl gas are mixed in a 1.50 L flask at 25 °C. < EFeedback You have not correctly determined the mass of NH,Cl formed. Identify the limiting reagent. Convert the given mass of the limiting reagent to the mass of NH,Cl using the NH; mole ratio from the balanced chemical HCI equation and the molar masses for both NH,CI the limiting reagent and the NH,Cl as conversion factors. How many grams of NH,Cl will be formed by this reaction? 0.273 mass: Incorrect What is the pressure in atmospheres of the gas remaining in the flask? Ignore the volume of solid NH,Cl produced by the reaction. P = 3.42arrow_forwardGiven the following decomposition reaction: 4C3H5O9N3 → O2 + 12CO2 + 10H2O +6N2. a. If 28.40 g H2O were produced, what mass of CO2 will be produced? b. If 110.5 g of C3H5O9N3 were decomposed and the yield of the reaction is 72.3%, determine the theoretical yield and actual yield.arrow_forward
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