A gas is formed in the reaction shown below. The gas laws can help determine the volume of gas produced. Zn(s) + 2 HCl(aq) → ZnCl, + H2(g) You have determined that 2.695 moles of H2(g) were produced in this reaction. At STP, what volume in L of H, will be produced? Remember the gas constant, R, is 0.08206 L·atm/mol·K.

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Title: Calculating Gas Volume at Standard Temperature and Pressure (STP)

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**Chemical Reaction and Gas Production**

In a chemical reaction, gas is produced as a result of the interaction described by the following equation:

\[ \text{Zn(s)} + 2 \text{HCl(aq)} \rightarrow \text{ZnCl}_2 + \text{H}_2(g) \]

**Problem Statement**

You have determined that 2.695 moles of \( \text{H}_2(g) \) were produced in this reaction.

**Question**

At standard temperature and pressure (STP), what volume in liters of \( \text{H}_2 \) will be produced?

**Important Information**

- The gas constant, \( R \), is 0.08206 L·atm/mol·K.
- Standard Temperature and Pressure (STP) is defined as 0°C (273.15 K) and 1 atm pressure.

**Approach to Solution**

To find the volume of hydrogen gas at STP, use the ideal gas law equation:

\[ PV = nRT \]

Where:
- \( P \) is the pressure (1 atm at STP)
- \( V \) is the volume in liters
- \( n \) is the number of moles (2.695 moles)
- \( R \) is the gas constant (0.08206 L·atm/mol·K)
- \( T \) is the temperature in Kelvin (273.15 K at STP)

Rearranging the formula to solve for volume:

\[ V = \frac{nRT}{P} \]

Substituting the known values:

\[ V = \frac{2.695 \times 0.08206 \times 273.15}{1} \]

Calculate this to find the volume of \( \text{H}_2 \) produced. 

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Transcribed Image Text:Title: Calculating Gas Volume at Standard Temperature and Pressure (STP) --- **Chemical Reaction and Gas Production** In a chemical reaction, gas is produced as a result of the interaction described by the following equation: \[ \text{Zn(s)} + 2 \text{HCl(aq)} \rightarrow \text{ZnCl}_2 + \text{H}_2(g) \] **Problem Statement** You have determined that 2.695 moles of \( \text{H}_2(g) \) were produced in this reaction. **Question** At standard temperature and pressure (STP), what volume in liters of \( \text{H}_2 \) will be produced? **Important Information** - The gas constant, \( R \), is 0.08206 L·atm/mol·K. - Standard Temperature and Pressure (STP) is defined as 0°C (273.15 K) and 1 atm pressure. **Approach to Solution** To find the volume of hydrogen gas at STP, use the ideal gas law equation: \[ PV = nRT \] Where: - \( P \) is the pressure (1 atm at STP) - \( V \) is the volume in liters - \( n \) is the number of moles (2.695 moles) - \( R \) is the gas constant (0.08206 L·atm/mol·K) - \( T \) is the temperature in Kelvin (273.15 K at STP) Rearranging the formula to solve for volume: \[ V = \frac{nRT}{P} \] Substituting the known values: \[ V = \frac{2.695 \times 0.08206 \times 273.15}{1} \] Calculate this to find the volume of \( \text{H}_2 \) produced. ---
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