A galvanic (voltaic) cell consists of an inert platinum electrode in a solution containing 1.0 M titanium(III) ion and 1.0 M titanium(II) ion, and another inert platinum electrode in a solution containing 1.0 M iron(III) ion and 1.0 M iron(II) ion, connected by a salt bridge. Calculate the standard potential for this cell at 25°C.

Questions 20 and 21 refer to the following information. Galvanic Cell Cell Diagram E°cell (Volts) Mg | Mg2(1.0 M) || Pb*2(1.0 M) | Pb 1 2.24 Zn | Zn(1.0 M) || Pb*2(1.0 M) | Pb 2 0.63 Mg | Mg*(1.0 M) || Zn*2(1.0 M) | Zn 3 The chemical reaction occurring in first galvanic cell is: Mg + Pb*2 → Mg+2 + Pb 21. If the concentration of Mg+2 is changed from 1.0 M to 3.0 M in the galvanic cells above, what will happen to the observed cell voltages in galvanic cells 1 and 3? (A) The voltage in both galvanic cells 1 and 3 will increase. (B) The voltage will decrease in both galvanic cells 1 and 3. (C) The voltage in galvanic cell 1 will increase and will decrease in galvanic cell 3 (D) The voltage in galvanic cell 3 will increase and will decrease in galvanic cell 1. 22. Consider a voltaic cell based on these half-cells. Ag (aq) +e → Ag/s) Cd (aq) + 2e → Cd¢s) E* = +0.80 V E = -0.40 V Identify the anode and give the voltage of this cell under standard conditions. (A) Ag; Ecell = 0.40 V (B) Ag;…

MnO4– + Sn ----> MnO2 + Sn2+ A) Identify the half-reaction that occurs at the cathode. B) Identify the oxidizing agent and anode. C) standard cell potential? D) What will be the potential of a cell constructed using 57.0 g MnO2, 1.57 M MnO4–, 14.8 g Pt, 12.5 g Sn and 0.87 M Sn2+ at pH 2.5?

A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II) ion solution and another electrode composed of gold in a 1.0 M gold(III) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25 °C. Refer to the list of standard reduction potentials. E° V 'cell * TOOLS х10

Consider the following voltaic cellat 25°C: Al(s) | Al3*(0.20 M, aq) || Al3+(0.75 M, aq) | Al(s) If the standard reduction potential for the Al3+(aq) /Al(s) redox couple is -1.66 V, what is the overall cell reaction and the cell potential of the voltaic cell shown above? (Reference the cell as written above.) The overall cell reaction is Al3+(0.75 M, aq) AIS*(0.20 M, ag) and E°cell = +0.0113 V. There is no overall cell reaction and E°cell = 0.00 V. The overall cell reaction is Al3+(0.20 M, aq) Als*(0.75 M, aq) and E°cell = +0.0113 V. The overall cell reaction is Al3+(0.20 M, aq) →A13+(0.75 M, ag) and E°cell| = -0.0113 V. The overall cell reaction is Al3*(0.75 M, aq) →AI3*(0.20 M, aq) and E°cell = -0.0113 V. None of these

Determine the ΔG° in KJ for a voltaic cell made of a Ag strip and a Pb strip immersed in 1.0 M aqueous AgNO3 and Pb(NO3)2 solutions, respectively, with all other cell components in place. (Use Table 18.3 for your standard cell potentials.)   Determine the thermodynamic equilibrium constant K for a voltaic cell made of a Zn strip and a Pb strip immersed in 1.0 M aqueous Zn(NO3)2 and Pb(NO3)2 solutions, respectively, at 25.00°C, with all other cell components in place. (Use Table 18.3 for your standard cell potentials.)

Cell Potential For a given galvanic cell, the standard cell potential can be calculated by subtracting the standard half-cell potential of the reaction that occurs at the cathode from the standard half-cell potential of the reaction that occurs at the anode: Ecell Ered (cathode) - Ed (anode) ▼ Tarnish on copper is the compound CuO. A tarnished copper plate i placed in an aluminum pan of boiling water. When enough salt is added so that the solution conducts electricity, the tarnish disappears. Imagine that the two halves of this redox reaction were separated and connected with a wire and a salt bridge. Part A Calculate the standard cell potential given the following standard reduction potentials: A²+ +3e Cu²+ + 20 Express your answer to two decimal places and include the appropriate units. ▸ View Available Hint(s) Ecell = li Value 4 → Units ? Al; E Cu; E 19 of 42 -1.66 V 0.340 V Review | Constants | Periodic Table

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Determine electromotive force for the cell represented by:             Fe (s) | FeSO4(0.30 M) || KIO3(0.50 M), l2(s), pH 4.0 | Pt(s)              Given:       Fe2+    + 2 e   ---------  Fe (s)          Eo  =   - 0.44                              Fe3+   +  e  ------   Fe2+                   Eo  =   0.771 V                                   IO3-   +  6 H+   +  5e  ------     ½ I2(s)   +  3 H2O (l)    E0 =   1.210 V       A. 1.346 V   B. 0.166 V   C. 1.376 V   D. 0.498 V   E. 1.660 V

A non-standard state galvanic cell is constructed at 25.00°C as described here.  The Fe(s) anode is immersed in a 0.040 M Fe(NO3)2 solution.  The Cu(s) cathode is immersed in a 0.0060 M Cu(NO3)2.  The circuit is completed with a salt bridge containing 1.0 M KNO3.  The standard Fe/Fe2+ reduction potential is –0.44 V.  The standard Cu/Cu2+ reduction potential is +0.34 V.  Calculate the non-standard-state cell potential for this galvanic cell and determine if the reaction described is spontaneous under these conditions.