A force of 24.0 N was used to push an object weighing 29.5 kg along a flat, frictionless, horizontal surface. What is the magnitude of the acceleration achieved by the object? A 8.0 m/s² B. 0.8 m/s² 1.2 m/s² D.O5.5 m/s2 C

A skydiver weighing 292 lbf (including equipment) falls vertically downward from an altitude of 4000 ft and opens the parachute after 10s of free fall. Assume that the force of air resistance, which is directed opposite to the velocity, is 0.77 |v| when the parachute is closed and 10|v| when the parachute is open, where the velocity v is measured in ft/s. Use g = 32 ft/s². Round your answers to two decimal places. (a) Find the speed of the skydiver when the parachute opens. v(10) = i (b) Find the distance fallen before the parachute opens. x(10) = i VL (c) What is the limiting velocity v after the parachute opens? = ft/s i ft ft/s

- Possible units of the moment M, are (a) kg/m. (b) kg -1 (c) m/kg. •m. 2

A soccer ball is kicked upward from a height of 2 ft with an initial velocity of 48 ft/s. How high will it go? Use -32 ft/s² for the acceleration caused by gravity. Ignore air resistance. Answer Maximum height: ft Keyp Keyboard Short