The person whose leg is shown in Figure 10.22 kicks his leg by exerting a 2000-N force with his upper legmuscle. The effective perpendicular lever arm is 2.20 cm. Given the moment of inertia of the lower leg is1.25 kg - m2, (a) find the angular acceleration of the leg. (b) Neglecting the gravitational force, what is therotational kinetic energy of the leg after it has rotated through 57.3° (1.00 rad)?Fr. = 2.20 cmFemur+\= 1.25 kg • m2Figure 10.22 The muscle in the upper leggives the lower leg an angular accelerationand imparts rotational kinetic energy to it byexerting a torque about the knee. Fis a vectorthat is perpendicular to r. This exampleexamines the situation.Solution to (a)From the rotational analog to Newton's second law, the angular acceleration a isnet Ta =10.101Because the force and the perpendicular lever arm are given and the leg is vertical so that its weight doesnot create a torque, the net torque is thusnet T(0.0220 m)(2000 N)= 44.0 N · m.10.102Substituting this value for the torque and the given value for the moment of inertia into the expression fora gives44.0 N · m1.25 kg · m2= 35.2 rad/s².a =10.103 3.3. In the OpenStax College Physics textbook, read the Chapter 10 sections 10.1 (AngularAcceleration), 10.3 (Dynamics of Rotational Motion: Rotational Inertia) and 10.5 (AngularMomentum and Its Conservation). Then write answers to [a] and [b] below.For all your answers, please write down your calculations and explain your reasoning. Drawsketches whenever helpful, and please use your units correctly. If you are using any onlineresources (such as unit conversion tools) give their URL and webpage title in your answers.[a] For Example 10.13 (Calculating the Torque in a Kick) in Section 10.5, replace “2000-N force"with "X-N force" where X is the number you computed on the first page of this study guide.Then solve part (a) of the example. There is no need to solve part (b).X = 883%3D

First we need to find torque due to force X-N and then using moment of inertia we can calculate…

[a] For Example 10.13 (Calculating the Torque in a Kick) in Section 10.5, replace "2000-N force" with "X-N force" where X is the number you computed on the first page of this study guide. Then solve part (a) of the example. There is no need to solve part (b). X = 883

[a] For Example 10.13 (Calculating the Torque in a Kick) in Section 10.5, replace "2000-N force" with "X-N force" where X is the number you computed on the first page of this study guide. Then solve part (a) of the example. There is no need to solve part (b). X = 883

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Plz use g = 9.8 m/s2 to find if needed
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