Correct this assignment and write a sentence or two explaining why I made the mistake a-AfoAx.Fall 20234. (5) For the member loaded as shown, with the smooth collar at A and roller support at B:Draw a complete Free Body Diagram (FBD) for the rigid body.b. Determine the support reactions necessary for equilibrium of the member.a.12Fy-маAx = 0=b- 2 Fx = 0(+5 ≤MA) = 0 Ay (3)AY900 N:500 N.m=A=1.5 m-1/2ByD900 N0okoopsSOON. m² =but500 N.m367N 17 -1211500 N·mBy- 10:37 NBy = 1037 NU-1.5 mAy - 900 - By cos 45º = 0By cos 45º = Ay - 900BYAy - 900cos450pë me dibrgot moment from900N, andTOMl By-hAy goes throughpoint A.HE45°00,1acts only in y-direction- 12pak21 IN1 mBATTskAx = 0Ay = 16+NABy 4037 NV

Answered: Image /qna-images/answer/8be97fcf-7d30-48ee-9450-69349f6fbd58.jpg

a- fo Ax. A a. 4. (5) For the member loaded as shown, with the smooth collar at A and roller support at B: Draw a complete Free Body Diagram (FBD) for the rigid body. b. Determine the support reactions necessary for equilibrium of the member. AY ма Ax 1 ≤ Fy=6 1 O 900 N : 500 N.m b- 2 Fx = 0 (52M₁) = 0 Ay (3) - 500 N. m² = 0 ΕΣΜΑ oups ok but Ay = 1 500 N.m 3 [AY = 267N 1) - 1/2 Ay - 900-By By cos 45° BY = 900 N -1.5 m A H 500 Nm By By = -1/2 BY TBY pe mie di go forgot moment from 900N, and -1.5 m Ay - 900 Ay - 900 cos450 -10 37 N 1037 N TOM 45° еву through Ay goes point A. 17 Of acts only in y-directin 24 cos 45º = 0 -Y₂ 1 m pairs) N Ax = 0 Ay = 16+NA Ov WASTNIN

a- fo Ax. A a. 4. (5) For the member loaded as shown, with the smooth collar at A and roller support at B: Draw a complete Free Body Diagram (FBD) for the rigid body. b. Determine the support reactions necessary for equilibrium of the member. AY ма Ax 1 ≤ Fy=6 1 O 900 N : 500 N.m b- 2 Fx = 0 (52M₁) = 0 Ay (3) - 500 N. m² = 0 ΕΣΜΑ oups ok but Ay = 1 500 N.m 3 [AY = 267N 1) - 1/2 Ay - 900-By By cos 45° BY = 900 N -1.5 m A H 500 Nm By By = -1/2 BY TBY pe mie di go forgot moment from 900N, and -1.5 m Ay - 900 Ay - 900 cos450 -10 37 N 1037 N TOM 45° еву through Ay goes point A. 17 Of acts only in y-directin 24 cos 45º = 0 -Y₂ 1 m pairs) N Ax = 0 Ay = 16+NA Ov WASTNIN

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A=1 B=2 C=2 Y=27
Two steel [E = 29,600 ksi] pipes (1) and (2) are connected at flange B, as shown in the figure. Pipe (1) has an outside diameter of 5.625 in. and a wall thickness of 0.255 in. Pipe (2) has an outside diameter of 4.375 in. and a wall thickness of 0.207 in. Assume L₁ = 12 ft and L₂= 21 ft. If the normal stress in each steel pipe must be limited to 16 ksi, determine (a) the maximum downward load P that may be applied at flange B. (b) the downward deflection of flange B at the load that you determined in part (a). L2 L₁ (1) C B
Advanced structural engineering
Subject structuur
The frame shown is supported by fixed support at E and smooth surface at A. Find: • the internal forces exerted by the internal Pin at B. Bx=... By=.. • The internal force at D 600 N 0.4 m B 0.4 m A E -0.3 m- -0.3 m- -0.3 m 3 m- -0.3 m-
Castigliano's theorem Continuous frame ABC has a pin at A, a guided bracket at C, and a rigid corner connection at B (see figure). The elements AB and BC have a bending stiffness El. Determine the magnitudes of the bending moment Mc and the reaction Hc. (Note: ignore axial strains in members AB and BC and consider only the effects of bending.) Mc -8 m- Hc B 4 m 16 kN. 4 m A
C8 please help me with the answer and full solution
Solve for Ay and By with FBD. (Please mention no.of reaction forces in supports for better understanding)
I could not solve this question, can you help me?
Question 6 A straight bar is fixed at edges A and B. Its elastic modulus is E and cross section is A. There is a load P = 100 N acting at C. The magnitude of the reactions at the ends A and B are L с P = 100 N 2L B
Subject MECHANICS OF MATERIALS AND STRUCTURES Civil Engineering please quick please
Before the uniform distributed load is applied on the beam, there is a small gap of 0.2 mm between the beam and the post at B. The post at B has a diameter of 40 mm, and the moment of inertia of the beam is I = 875 (10°) mm“. The post and the beam are made of material having a modulus of elasticity of E = 200 GPa. Part A Determine the support reaction at A. Take w = 27 kN/m . (Figure 1) Express your answer with the appropriate units. HÀ A, - Value Units Submit Request Answer Part B Determine the support reaction at A. Express your answer with the appropriate units. igure 1 of 1 A, - Value Units Submit Request Answer Part C Determine the support reaction at B. I m |B 0.2 mm Express your answer with the appropriate units. 6 m 6 m ? By = Value Units