Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- For the system shown below, compute the (a) gage pressure and (b) absolute pressure at point A. The atmospheric pressure is 14.7 psi. Express the pressures in psi (Ib/in?). Oil (SG = 0.85) Water 6 in A Mercury (SG = 13.6) 9 in 7 inarrow_forwardDetermine the gauge pressure at the center of pipe B in kilopascals. Mercury (S = 13.6) is the fluid in the manometer while oil (S = 0.93) is the fluid flowing in the pipe. Oil Mercury +B 0.2 m 0.02 marrow_forwardThe gage pressure of the air in the tank shown in figure is measured to be 65 kPa. Determine the differential heighth of the mercury column. 65KPA Oil ŚG = 0.72 75cm Air Water Mercury SG - 13.6 30cmarrow_forward
- Q2: Compute the value of (H) in centimeters such that the pressure at B is 90% of the pressure at point A. If the pressure at A is 79.4 kPa, S.G (oil)=0.89, S.G (mercury)=13.6. SAE 30 oil Gage B Mercury- 6 сm H Water flow 11 cm 4 cmarrow_forward1.) A pressure in a given tank reads 398 mm of Hg. Determine the equivalent height of a certain fluid in m with sp.gr= 4.33.arrow_forwardIn figure 3 compute the pressure head difference between m and n, in feet of fluid A, when: A. Fluid A is gasoline (sp gr 0.715), the gage liquid is mercury, and z = 47.77 in B. Fluid A is oil (sp gr 0.908), the gage liquid is water, and z = 27.77 in C. Fluid A is sea water (w = 64.0), the gage liquid has a specific gravity of 2.95, and z = 57.77arrow_forward
- I need answer within 20 minutes please please with my best wishesarrow_forwardA U-tube manometer is connected to a closed tank containing air and water as shown in the figure below. At the closed end of the manometer the air pressure is 17 psia. Determine the reading on the pressure gage for a differential reading of 6 ft on the manometer. Express your answer in psi (gage). Assume standard atmospheric pressure and neglect the weight of the air columns in the manometer. Assume Pair = 17 psia, h₁ = 3 ft, h₂ = 6 ft. Pgage = psi -Closed valve -Air pressure = P Gage fluid (y = 90 lb/ft³) air Air Water Pressure gagearrow_forwarddiameter = 60 cm height = 60 cm The CLOSE cylindrical tank is two-thirds full of water. It is subjected to pressure = 10 kpag. Considering that the tank is to rotate about the axis at the center at 10 rad/s a. What is the pressure at point C? b. What is the pressure at point D?arrow_forward
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