A fluid expands reversibly according to a linear law from 3.8 bar to 1.1 bar, the initial volume is 0.006 mº. The fluid is then cooled reversibly at constant pressure, and finally compressed reversibly according to a law pv =constant back to the initial conditions of 3.8 bar and 0.006 m. Calculate the net work of the cycle if the work done during the constant pressure cooling is given by 5930 N.m. Sketch the cycle on a p-v diagram.

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Answered: A fluid expands reversibly according to…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A gas with specific volume v₁ = 1 m³/Kg and pressure p₁=1bar in a closed system undergoes a thermodynamic cycle which consists of the following three separate processes: 1->2: Isobaric compression to v₂-0.25 m³/Kg 2->3: Isometric heating. 3->1: Isothermal expansion (pV = constant) to the initial volume. Calculate the specific work produced by the gas per cycle. Present your answer in kJ/kg.
A fluid at 0.7 bar occupying 0.06 m is compressed reversibly to a pressure of 95 bar and specific volume of 0.7 mkg according to the law pv" =c The fluid then expands reversibly according to the law p=c to 3 bar. A reversible cooling at constant volume then restores the fluid back to initial state Calculate the work for the compression in the process.
Water vapors at 40 bar enters a pipe fitting (adapter) with a velocity of 169 m/s and exits thefitting at 10 bar and 572°F. If the temperature at the inlet is 1004°F., calculate the exit velocity.The system is assumed to be at steady state.
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A fluid at 0.5 bar occupying 0.08 m3 is compressed reversibly to a pressure of 10.9 bar and specific volume of 0.6 m3/kg according to the law pvn = c. The fluid then expands reversibly according to the law pv2 = c to 1.6 bar. A reversible cooling at constant volume then restores the fluid back to initial state. Calculate the net work for the process in Joules.

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