College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A cube has sides of length L = 0.370 m. It is placed with one corner at the origin as shown in the figure (Figure 1). The electric field is not uniform but is given by E =(-5.69 N/(C. m) )æi+(3.20 N/(C - m) )zk. Part A Find the electric flux through each of the six cube faces S1, S2, S3, S4, S5. and S6. Enter your answers numerically separated by commas. Eν ΑΣφ ? d1, Þ2, Þ3 , 4 , Þ5 , Þ6 = (N/C) - m² Submit Previous Answers Request Answer Part B Find the total electric charge inside the cube. ΑΣφ ? q = Figure 1 of 1 Submit Request Answer S2 (top) So (back) Provide Feedback S3 (right side) (left side) L L L. S, (bottom) S, (front)arrow_forwardDETAILED WORK STEP AND WRITE CLEARLY PLEASE. asaparrow_forwardPart A A conducting sphere has a net charge of Q = 8nC and a radius of r= 10cm. What is the surface charge density? να ΑΣφ nC/m2 Submit Request Answerarrow_forward
- please answer all parts and explanation.arrow_forwardThe electric flux through each of the six sides of a rectangular box are as follows 4 =155 3 N-m/C, 4 = 236 4 N.m/C =-334 3 N.m/C ,-173 8 N.m/C 4--1118 N.m²/C d= 448 0 N m²/C. V Part A How much charge is in this box? PC Submit Previous Answers Request Answer * Incorrect Try Again; 5 attempts remainingarrow_forwardPart A A closed surface encloses a net charge of 3.10 μC . What is the net electric flux through the surface? Express your answer in newton-meters squared per coulomb. %0 ΑΣΦ Submit Request Answer Part B Submit ? If the electric flux through a closed surface is determined to be 2.20 Nm²/C, how much charge is enclosed by the surface? Express your answer in coulombs. IVE ΑΣΦ Request Answer N.m²/C ? C Pearsonarrow_forward
- A 1.4 cm x 1.4 cm x 1.4 cm box with its edges aligned with the xyz-axes is in the electric field E = (370x + 150) i N/C, where x is in meters. Part A What is the net electric flux through the box? Nm2/Carrow_forwardA cube has sides of length L = 0.370 m. It is placed with one corner at the origin as shown in the figure (Figure 1). The electric field is not uniform but is given by E =( -5.69 N/(C. m) )æi+( 3.20 N/(C · m) )zk. Part A Find the electric flux through each of the six cube faces Sı, S2, S3, S4, S5, and Sg- Enter your answers numerically separated by commas. ν ΑΣφ D1, Þ2 , D3 , Þ4 , Þ5 , Þ6 = (N/C) - m² Submit Request Answer Part B Find the total electric charge inside the cube. q = Figure 1 of 1 Submit Request Answer S2 (top) S6 (back) Provide Feedback S1 (left side) L - S3 (right side) y L L. S4 (bottom) S3 (front)arrow_forwardI Rew A spherically symmetric charge distribution produces the electric field E =( 5700 r2)r N/C, where r is in m. Part A What is the electric field strength at r = 19.0 cm ? ? N/C Submit Request Answer Part B What is the electric flux through a 38.0-cm-diameter spherical surface that is concentric with the charge distribution? Nm2/C Submit Request Answer Part C How much charge is inside this 38.0-cm-diameter spherical surface? Carrow_forward
- Electric Fields 1. A wire has been given a net positive electric charge Q evenly distributed along its length. The wire has a length of L and is located on the x-axis with its left end at the origin as drawn. Set up the integral you need to do to find the electric field at a distance d to the left of the origin. Some steps you may wish to follow are: a. Figure out the direction the electric field will have at our location x = -d. This will be the same as f b. Write the differential charge dą in terms of the charge per length and a differential length. c. ris a function of x which means we have to integrate to find the electric field. Write down r. d. Put everything together (including the vector direction) into one integral that would allow you to find the E-field. Write this in the box below. e. You are not required to complete the integral and no credit is given for completing the integral. d dE =arrow_forwardB) A uniform electric field is shown below. Using the information given, answer the questions shown. * A [1 * C D :Smallest A=(-1m,2m) C=(1m,2m) Rank, from largest to smallest the electric field at each of the points shown above. If two or more choices are equal, indicate this by putting an equal sign "=" between the letters in the ranking. B=(-1m,-1m) D=(1m,-1m) Largest: Rank, from largest to smallest the magnitude of the force on an electron placed at each of the points shown above. If two or more choices are equal, indicate this by putting an equal sign "=" between the letter in the ranking. Largest: :Smallest :Smallest O Rank, from largest to smallest the electric potential at each of the points shown above. If two or more choices are equal, indicate this by putting an equal sign "-" between the letters in the ranking. Largest: ) Rank, from largest to smallest the potential energy an electron would have if it were placed at each of the points shown. If two or more choices are…arrow_forward
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