A flask is charged with 1.720 atm of N₂O4(g) and 0.88 atm NO₂(g) at 25°C. The equilibrium reaction is given in the equation below. N₂04(9) 2NO₂(g) After equilibrium is reached, the partial pressure of NO₂ is 0.512 atm. (a) What is the equilibrium partial pressure of N₂O4? 1.904 ✔atm (b) Calculate the value of K, for the reaction. 0.137 ✔ (c) Is there sufficient information to calculate K for the reaction? O Yes, because the partial pressures of all the reactants and products are specified. Yes, because the temperature is specified. O No, because the value of K. can be determined experimentally only. If K can be calculated, find the value of K. Otherwise, enter 0. 2.30e-4 x

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Chapter12: Chemical Equilibrium
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A flask is charged with 1.720 atm of N₂O4(g) and 0.88 atm NO₂(g) at 25°C. The equilibrium reaction is given in the equation below.
N₂04(9) 2NO₂(g)
After equilibrium is reached, the partial pressure of NO₂ is 0.512 atm.
(a) What is the equilibrium partial pressure of N₂O4?
1.904
atm
(b) Calculate the value of K, for the reaction.
0.137
(c) Is there sufficient information to calculate K for the reaction?
O Yes, because the partial pressures of all the reactants and products are specified.
Ⓒ Yes, because the temperature is specified.
O No, because the value of K. can be determined experimentally only.
If K can be calculated, find the value of K. Otherwise, enter 0.
2.30e-4
X
Transcribed Image Text:A flask is charged with 1.720 atm of N₂O4(g) and 0.88 atm NO₂(g) at 25°C. The equilibrium reaction is given in the equation below. N₂04(9) 2NO₂(g) After equilibrium is reached, the partial pressure of NO₂ is 0.512 atm. (a) What is the equilibrium partial pressure of N₂O4? 1.904 atm (b) Calculate the value of K, for the reaction. 0.137 (c) Is there sufficient information to calculate K for the reaction? O Yes, because the partial pressures of all the reactants and products are specified. Ⓒ Yes, because the temperature is specified. O No, because the value of K. can be determined experimentally only. If K can be calculated, find the value of K. Otherwise, enter 0. 2.30e-4 X
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